What value of w makes the following equation true? w+4 1 over 5 = 13 19 over 20

Solving systems of equations using substitution p=q+2 4p+3q= -27

GREYUIT [131]

Ok, so you are given the value of P=q+2

The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27

Doing so will give us 4(q+2)+3q= -27

For right now, lets just focus on the first part, 4(q+2)

We can simplify this by distributing(multiplying) the 4 to whats inside the variables.

This will give us 4q+8

now lets add this back to the rest of the equation >>> 4q+8+3q = -27

We can further simplify by adding like terms >>> 7q+8 = -27

subtract the 8 from both sides >>> 7q = -35

now divide both sides by 7 >>> q = -35/7

Therefor q = -5

EDIT*

now that we know q = -5 we can put q into the equation for P !

we know that p=q+2

so lets put q in now >>> p=(-5)+2

and simplify>>> p = -3

I hope this helps:)

6 0

4 years ago

I NEEEED HELP!!! please show work in answer and no blank or nonsense answers please :)

rodikova [14]

Answer:

225 pi = pi r^2 h

225 = r^2*h

225/1 = r^2

sqrt. (225) = r

r = 15

8 0

3 years ago

Kiara desea contratar el servicio de una línea telefónica con internet para realizar sus clases virtuales. Si el costo de una lí

ArbitrLikvidat [17]

a) Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo "Expresa" como "Describa en sus propias palabras".

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

$C(t) = C_{o} + r\cdot t$ (1)

Donde:

$C_{o}$ - Coste fijo, en soles.
$r$ - Tasa de consumo, en soles por hora.

Entonces, tenemos que Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) Una característica de las Funciones Lineales es que tanto su Dominio como Rango comprenden al Conjunto de todos los Números Reales, al ser de Pendiente constante esta Función.

Por tanto, el Dominio y el Rango de la Función en cuestión es el Conjunto de todos los Números Reales.

c) Si sabemos que $C_{o} = 10$ , $r = 1,5$ y $t = 48$ , entonces el Coste Total por concepto de 48 horas de consumo es:

$C(48) = 10 + 1,5\cdot (48)$

$C(48) = 82$

El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

Invitamos a ver este problema sobre Costes: brainly.com/question/15723794

7 0

3 years ago

A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec

VMariaS [17]

Answer:

$19.1-3.355\frac{1.5}{\sqrt{9}}=17.42$

$19.1+3.355\frac{1.5}{\sqrt{9}}=20.78$

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=19.1$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=9-1=8$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that $t_{\alpha/2}=$