<span>3p + 13 = 37
Subtract 13 from both sides
3p=24
Divide 3 on both sides
Final Answer: p=8</span>
Her sample space is also the list of local businesses.
Sampling is a technique used in statistics when researchers choose a representative subset of a larger population and utilize that subset to carry out a study. Probability sampling and non-probability sampling are the two main types of sampling. Selecting the group from whom you will actually gather data for your study is the process of sampling. If you wanted to examine the perspectives of students at your university, for instance, you could interview a sample of 100 students. With the help of sampling, you can test a statistical hypothesis on the features of a population.
The yellow pages are used by the researcher to do research on neighborhood companies. As a result, her sample space also includes a list of nearby companies.
Complete question: A researcher is conducting a study on local businesses. In order to create her sample, she uses the Yellowpages and a dice. She rolls the dice, and, depending on the number rolled, counts that many businesses down in the list to call. What is her sampling frame?
The list of local businesses in the Yellowpages.
All businesses within a
radius.
The list of local businesses in the newspaper.
All businesses in the state she is located in.
The list of registered businesses in her area.
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(2 + a) = (a + 2) it's commutative property
(a + 2) - 7 = a + (2 - 7) it's associative property
2 - 7 = -5 it's subtraction
Answer: distributive property { a(b + c) = ab + ac }
Answer: We support the null hypothesis.
Step-by-step explanation:
Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
The set of hypothesis for the given claim :-

A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).
Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).
Therefore, we support the null hypothesis.
So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
Step-by-step explanation:
in the 6 th process I've used natural logarithm ln and ln(e)=1.
if the answer is required in decimal u can substitute the value in calculator.
hope it helps