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2 years ago

6 veces un numero elevado al cuadrado.

Mathematics

1 answer:

Lunna [17]2 years ago

4 0

Answer:

Six squared=36

Step-by-step explanation:

Well, we know squared means 2

So...Think.

Six is not times 2. You might think that, but...

...It's actually multiplying 6 two times

6x6 is 36

You also can think of it as

6x(6 two times)

or 6x(3x2)

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Four books, one each on physics, chemistry, mathematics, and biology are about to be stacked on a shelf. If the books are stacke

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Mary's job is to package kleenex boxes to ship out to sell at stores. the company

swat32

Volume is a three-dimensional scalar quantity. The number of kleenex boxes that can fit in the large box is 4096.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the larger box have a length of the side as 4 feet. Also, the kleenex box is a cube with side lengths of 3 inches. Therefore, the number of cubes that will fit is,

Number of boxes = Volume of Larger box / Volume of kleenex box

Number of box = (4 feet)³ / (3 inches)³

Number of box = (48 inches)³ / (3 inches)³

Number of box = 4096

Hence, the number of kleenex boxes that can fit in the large box is 4096.

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1 year ago

some friends need 100 bows for a project Sara brings 12 bows Angela brings 50 bows and Nora brings 34 bows how many more bows do

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They need 4 more because 12+50+34=96 96-100 is 4 hope this helps ya

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3 years ago

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Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number

sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

$E(X)=\sum x\cdot P(X=x)$

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner: 1 2 3 4 5 6

Amount earned (<em>X</em>): $1 $4 $7 $10 -$8.75 -$8.75

Probability: 1/6 1/6 1/6 1/6 1/6 1/6

Compute the expected value of <em>X</em> as follows:

$E(X)=\sum x\cdot P(X=x)$

$=(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})$

$=\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}$

$=\frac{1+4+7+10-8.75-8.75}{6}$

$=0.75$

Thus, the expected value of playing the game is $0.75.

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