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Flura [38]
3 years ago
10

.

Chemistry
2 answers:
krok68 [10]3 years ago
6 0

Answer:

True

Explanation:

It's a true statement

Rudiy273 years ago
4 0

Answer:

True

Explanation:

A species is a group of similar organisms that can breed with one another to produce fertile offspring. For example, humans are one species and dogs are another species. Individuals of the same species can reproduce to make more individuals of the same species.

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Ced
Aleks [24]

Answer:

c

Explanation:

7 0
3 years ago
The graph below shows the volume and the mass of four different substances at STP.
sladkih [1.3K]
The formula of density is mass / volume

This means that
- high mass, low volume = high density
- high mass, high volume = so-so
- low mass, high volume = low density

From the graph shown, 
D has the lowest density because it has low mass yet high volume.
6 0
4 years ago
Help me solve the question please I'm a struggling college student
Archy [21]
What is the question
8 0
3 years ago
Read 2 more answers
Antacids, such as Alka-Seltzer, use the reaction of sodium bicarbonate with citric acid in water solution to produce a fizz as f
Alex17521 [72]

Answer:

2.8248 g

Explanation:

First, consider the balanced chemical equation:

3NaHCO_{3} +C_{6}H_{8}O_{7} --->3CO_{2} +3H_{2}O +Na_{3}C_{6}H_{5}O_{7}\\

Then we calculate the number of moles in 4.11 g of citric acid:

n(citric acid)=\frac{4.11g}{192g/mol}=0.0214mol

According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.

so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol

mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol

                                                                   = 2.8248 g

8 0
3 years ago
If 6.0g of carbon is heated in air the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of ai
Gnom [1K]

In accordance with Dalton's Law of multiple proportions

<h3>Further explanation</h3>

Given

6.0g of carbon

22.0g or 14.0g of product

Required

related laws

Solution

the amount of air present ⇒ as an excess or limiting reactant

  • air(O₂) as a limiting reactant(product=14 g)

C+0.5O₂⇒CO

6 + 8 = 14 g

mol O₂=8 g : 32 g/mol=0.25

mol C = 6 g : 12 g/mol = 0.5(2 x mol O₂)

mol CO= 2 x mol O₂ = 0.5 mol = 0.5 x 28 g/mol = 14 g

  • air(O₂) as an excess reactant(product=22 g) an C as a limiting reactant

C+O₂⇒CO₂

6 + 16 = 22 g

mol C = 6 g : 12 g/mol = 0.5

mol O₂ = 16 g : 32 g/mol=0.5

mol CO₂ = 22 g : 44 g/mol = 0.5

if the mass firs element (C) constant, then the mass of the second element(O) in the two compounds will have a ratio as a simple integer.

CO = 6 : 8

CO₂ = 6 : 16

the ratio O = 8 : 16 = 1 : 2

In accordance with Dalton's Law of multiple proportions

4 0
3 years ago
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