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NISA [10]
2 years ago
10

What compounds make up the cells and other structures of organisms and carry out what process?

Chemistry
1 answer:
masya89 [10]2 years ago
3 0

Answer:

Biochemical compounds make up the cells and other structure of organism and carry out life processes.Carbon is the basic of all biochemical compounds so carbon carried life process on the earth

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The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equati
valkas [14]

Answer:

(a) p_{C6H5CH2OH}=2.14x10^{-3}atm

(b) Dissociation =0.99

Explanation:

Hello,

(a) In this case, for the given chemical reaction, the law of mass action becomes:

Kc=\frac{[C6H5CHO][H2]}{[C6H5CH2OH]}

In such a way, as 1.20 g of benzyl alcohol are placed into a 2.00-L vessel, the initial concentration is:

[C6H5CH2OH]_0=\frac{1.20g*\frac{1mol}{108.14g} }{2.00L} =5.55x10^{-3}M

Hence, by writing the law of mass action in terms of the change x due to equilibrium:

Kc=\frac{(x)(x)}{5.55x10^{-3}-x}=0.558

Solving for x by using a quadratic equation one obtains:

x=5.50x10^{-3}M

Thus, the equilibrium concentration of benzyl alcohol is computed:

[C6H5CH2OH]_{eq}=5.55x10^{-3}M-5.50x10^{-3}M=5x10^{-5}M

With that concentration the partial pressure results:

p_{C6H5CH2OH}=[C6H5CH2OH]_{eq}RT =5x10^{-5}\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*523K \\p_{C6H5CH2OH}=2.14x10^{-3}atm

(b) Now, the fraction of benzyl alcohol that is dissociated relates its equilibrium concentration with its initial concentration:

Dissociation=\frac{C6H5CH2OH_{eq}}{C6H5CH2OH_0} =\frac{5.50x10^{-3}M}{5.55x10^{-3}M} =0.99

Best regards.

3 0
3 years ago
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Answer:

Polarity results from an unequal sharing of valence electrons. In SO3 there is the sharing is equal. Therefore SO3 is a nonpolar molecule.

Explanation:

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the formula is(NH4)2SO4

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Explanation:

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