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andrezito [222]
3 years ago
14

As the moon orbits the ______________, its gravitational pull is______________ on the side of the earth closest to the _________

_____.This ______________ force pulls on the water facing the moon,creating a ______________. The moon also ______________ on the solidearth, causing the water on the far side of earth to ______________as well. These bulges in the water are the ______________.The areas in between the close and far side of the earth which are not in ______________ with the moon experience ______________.
pls help i give brainlyest
Chemistry
1 answer:
Fynjy0 [20]3 years ago
5 0

Answer:

Earth

Strongest

Moon

Gravitational

Tide

Pulls

Bulge

Waves

Proximity

Low Tide

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Strong acids have a ______ value of Ka and the equlibrium for the reaction with water lies far to the _______.
nika2105 [10]

Answer:

All strong acids have a higher value of K_{a} and the equilibrium for the reaction with water lies far to the right.

Explanation:

All strong acids dissociate completely in the solution. Higher the value of dissociation constant of the acid, higher will be the dissociation of the acid.

The reaction of the acid with water will be favored in the forward direction for acids having higher dissociation constant value (K_{a}).

The dissociation of a strong acid say HA in water is shown below\textrm{HA}\left ( aq \right )+\textrm{H}_{2}\textrm{O}\left ( l \right )\rightleftharpoons \textrm{A}^{-}\left ( aq \right )+\textrm{H}_{3}\textrm{O}^{+}\left ( aq \right )

Higher the value of K_{a}, more will be the dissociation of the acid in water. The reaction will move far to the right side.

4 0
3 years ago
The free energy obtained from the oxidation (reaction with oxygen) of glucose (C6H12O6) to form carbon dioxide and water can be
babunello [35]

Answer:

The correct answer is -2878 kJ/mol.

Explanation:

The reaction that takes place at the time of the oxidation of glucose is,  

C₆H₁₂O₆ (s) + 6O₂ (g) ⇒ 6CO₂ (g) + 6H₂O (l)

The standard free energy change for the oxidation of glucose can be determined by using the formula,  

ΔG°rxn = ∑nΔG°f (products) - ∑nΔG°f (reactants)

The ΔG°f for glucose is -910.56 kJ/mol, for oxygen is 0 kJ/mol, for H2O -237.14 kJ/mol and for CO2 is -394.39 kJ/mol.  

Therefore, ΔG°rxn = 6 (-237.14) + 6 (-394.39) - (-910.56)

ΔG°rxn = -2878 kJ/mol

8 0
3 years ago
Which element, when combined with Iodine, would most likely form an ionic compound?
uranmaximum [27]

In an ionic compound the atoms are linked via ionic bonds. These are formed by the transfer of electrons from one atom to the other. The atom that loses electrons gains a positive charge whereas the atom that accepts electrons gains a negative. This happens in accordance with the octet rule wherein each atom is surrounded by 8 electrons

In the given example:

The valence electron configuration of Iodine (I) = 5s²5p⁵

It needs only one electron to complete its octet.

In the given options:

K = 4s¹

C = 2s²2p²

Cl = 3s²3p⁵

P = 3s²3p³

Thus K can donate its valence electron to Iodine. As a result K, will gain a stable noble gas configuration of argon while iodine would gain an octet. This would also balance the charges as K⁺I⁻ creating a neutral molecule.

Ans: Potassium (K)

4 0
3 years ago
Which of the statements about peptide bonds are true? The formation of a peptide bond involves a dehydration reaction. A tripept
Mashcka [7]

Answer:

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

Explanation:

Peptide bond is a form of covalent bond and it is Amide type that is formed between two molecules when carboxyl group react with one molecule of amino group to release molecule of water.The peptide bond are in form pseudo-double bond characteristic; rigid, planar, and stronger than a typical Carboxyl nitrogen single bond.

Peptide bonds form from nucleophilic attack by an α‑carboxyl carbon atom on an electron pair of an α‑amino nitrogen atom of another amino acid.

3 0
3 years ago
We identify nucleic acid strand orientation on the basis of important chemical functional groups. These are the _________ group
zloy xaker [14]

Answer:

We identify nucleic acid strand orientation on the basis of important chemical functional groups. These are the <u>phosphate</u> group attached to the 5' carbon atom of the sugar portion of a nucleotide and the <u>hydroxyl</u> group attached to the <u>3'</u> carbon atom

Explanation:

Nucleic acids are polymers formed by a phosphate group, a sugar (ribose in RNA and deoxyribose in DNA) and a nitrogenous base. In the chain, the phosphate groups are linked to the 5'-carbon and 3'-carbon of the ribose (or deoxyribose) and the nitrogenous base is linked to the 2-carbon. Based on this structure, the nucleic acid chain orientation is identified as the 5'-end (the free phosphate group linked to 5'-carbon of the sugar) and the 3'-end (the free hydroxyl group in the sugar in 3' position).

3 0
3 years ago
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