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3 years ago

14

Write the equation for a parabola with the focus at

2 answers:

katen-ka-za [31]3 years ago

5 0

The answer is (y - 4)2 = -12(x - 2)
Since the graph is facing the left, the starting equation would be (y - k)2 = -4p(x - h).
(h, k) is the vertex of the graph. If you plot the focus and the directrix, you can see that the distance is 6. Divide 6 by 2, thus the vertex should be 3 squares away from the focus and 3 squares away from the directrix. The vertex is (2, 4). And since the distance from the focus to the vertex and the distance from the directrix to the vertex is 3, P = 3.
Insert the numbers in and you should get the last choice.

Flura [38]3 years ago

3 0

Answer:

d

Step-by-step explanation:

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ladessa [460]

Given:

$AB=6\ BC=r,\ CD=r,\ AD=12$ .

To find:

The value of r.

Solution:

We have,

$AB=6\ BC=r,\ CD=r,\ AD=12$ .

We know that the radius is perpendicular to the tangent at the point of tangency

AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., $m\angle D=90^\circ$ .

Using Pythagoras theorem, we get

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2 years ago

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Dmitry [639]

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3 years ago

A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond

Fiesta28 [93]

The time required for one wing beat is 5 milliseconds.

<em><u>Explanation</u></em>

Lets assume, the time required for one wing beat is $t$ seconds

So, the time required for 200 wing beat $= 200t$ seconds

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