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2 years ago

Find the volume of the rectangular prism. Enter your answer in the box

Mathematics

2 answers:

SOVA2 [1]2 years ago

8 0

Answer:

151.7 cm^3

Step-by-step explanation:

If you didn't know already the volume of a rectangular prism is

length x witdh x height.

Multiply 10x4.1 and you will get 41

Then multiply 41 by 3.7 to get 151.7.

Vera_Pavlovna [14]2 years ago

6 0

Answer:

151.7 cm^3

Step-by-step explanation:

3.7 x 10 x 4.1 = 151.7

BRAINLIEST? TY!!

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The dimensions of a rectangle can be given by x+9 and x-2. If the area is 60ft^2, what is the value of X?

Veronika [31]

Answer:

Step-by-step explanation:

(x + 9) * (x - 2) = 60

x^2 - 2x + 9x - 18 = 60

x^2 + 7x - 18 = 60

x^2 + 7x = 78

FACTORING:

x(x + 7) = 78

x = 6

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3 years ago

The Japanese Yen corresponds to the American Dollar. If the exchange rate is 150 Yen for 1 Dollar, then a Japanese car sold in A

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Answer:

125,000

Step-by-step explanation:

Take the Japanese yen and divide by 12

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4 years ago

Seven values on the number line above are marked with letters. Match the opposites.

Natali [406]

Answer:

Step-by-step explanation:

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3 years ago

Given that y varies directly with x, find the equation of direct variation.<br> x is 14 when y is 12

Sergeu [11.5K]

Step-by-step explanation:

x×k = y

14×k = 12

k = 12/14 = 6/7

so, the equation is

x × 6/7 = y

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5 0

2 years ago

Find the perimeter P of ▱JKLM with vertices J(−3,−2), K(−5,−5), L(1,−5), and M(3,−2). Round your answer to the nearest tenth, if

Bezzdna [24]

Given:

Vertices of JKLM are J(−3,−2), K(−5,−5), L(1,−5), and M(3,−2).

To find:

The perimeter P of a parallelogram JKLM.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$JK=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(-5-\left(-2\right)\right)^2}$

$JK=\sqrt{\left(-5+3\right)^2+\left(-5+2\right)^2}$

$JK=\sqrt{\left(-2\right)^2+\left(-3\right)^2}$

$JK=\sqrt{4+9}$

$JK=\sqrt{13}$

Similarly,

$KL=\sqrt{\left(1-\left(-5\right)\right)^2+\left(-5-\left(-5\right)\right)^2}=6$

$LM=\sqrt{\left(3-1\right)^2+\left(-2-\left(-5\right)\right)^2}=\sqrt{13}$

$JM=\sqrt{\left(3-\left(-3\right)\right)^2+\left(-2-\left(-2\right)\right)^2}=6$

Now, perimeter P of ▱JKLM is

$P=JK+KL+LM+JM$

$P=\sqrt{13}+6+\sqrt{13}+6$

$P=2\sqrt{13}+12$

$P=2(3.61)+12$

$P=7.22+12$

$P=19.22$

$P\approx 19.2$

Therefore, the perimeter P of ▱JKLM is 19.2 units.

3 0

3 years ago