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Whitepunk [10]
3 years ago
13

Are these correct? If not please help me write the correct answer.​

Mathematics
2 answers:
Llana [10]3 years ago
8 0

Answer:

i = correct

ii = correct

iii = correct

iv = correct

4

i = 16/81 => 0.1975308642

ii= 1/64

Keith_Richards [23]3 years ago
4 0

Answer:

Mostly correct

For Q3, you are doing great, you remembered that negative numbers can happen if the exponent is an odd number.

For Q4, I think you were confused with the fractions,

4(i)

(\frac{2}{3} )^{4} = (\frac{2^{4}}{3^{4}}) = (\frac{16}{81}) =0.198

4(ii) is also wrong but I'll let you try to fix it yourself following what I given you for 4(i). You should get 1/64

Hope this helps!

You might be interested in
Please help with this question
astraxan [27]

Answer:

x = -8/2

Step-by-step explanation:

To make the equation easier to work with, our first step will be to make all of our fractions have a common denominator. Both 2 and 4 are factors of 8, so that will be our common denominator.

Old Equation: 1/4x - 1/8 = 7/8 + 1/2x

New Equation (with common denominators): 2/8x - 1/8 = 7/8 + 4/8x

Now, we're going to begin to isolate the x variable. First, we're going to subtract 2/8x from both sides, eliminating the first variable term on one side completely.

2/8x - 1/8 = 7/8 + 4/8x

-2/8x                    -2/8x

__________________

-1/8 = 7/8 + 2/8x

We're one step closer to our x variable being isolated. Next, we're going to move the constants to the left side of the equation. To do this, we must subtract by 7/8 on both sides.

-1/8 = 7/8 + 2/8x

- 7/8  -7/8

______________

-1 = 2/8x

Our last step is to multiply 2/8x by its reciprocal in order to get the x coefficient to be 1. This means multiply both sides by 8/2.

(8/2)  -1 = 2/8x (8/2)

The 2/8 and 8/2 cancel out, and you're left with:

-8/2 = x

I hope this helps!

7 0
3 years ago
Can someone be so freaking awesome and help me out with the correct answer please :( !?!?!?!?!???!!! 30 points!!!
Sindrei [870]

\bf 7~~,~~\stackrel{7+6}{13}~~,~~\stackrel{13+6}{19}~~,~~\stackrel{19+6}{25}\qquad \impliedby \qquad \textit{common difference "d" is 6}

we know all it's doing is adding 6 over again to each term to get the next one, so then

\bf \stackrel{\textit{Recursive Formula}}{\stackrel{\textit{nth term}}{f(n)}~~=~~\stackrel{\textit{the term before it}}{f(n-1)}~~~~\stackrel{\textit{plus 6}}{+~~~~6}}

now for the explicit one

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=7\\ d=6 \end{cases} \\\\\\ a_n=7+(n-1)6\implies a_n=7+6n-6\implies \stackrel{\textit{Explicit Formula}}{\stackrel{f(n)}{a_n}=6n+1} \\\\\\ therefore\qquad \qquad f(10)=6(10)+1\implies f(10)=61

3 0
3 years ago
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
Read 2 more answers
Help on this one. You will get 10 points
ad-work [718]

Answer:

A.true

Step-by-step explanation:

The domain of a quadratic function in standard form is always all real numbers, meaning you can substitute any real number for x. The range of a function is the set of all real values of y that you can get by plugging real numbers into x.

8 0
3 years ago
Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
8 0
3 years ago
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