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postnew [5]
2 years ago
14

A Mathematics paper consists of 12 questions of which not more than ten are to be answered. Given that the number of candidates

who answer ten questions is equal to the number of candidates who answer nine questions only. Find the probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 if all the questions have the same chance of being selected.​
Mathematics
1 answer:
RUDIKE [14]2 years ago
7 0

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.

<h3>How to calculate probability?</h3>

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:

= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]

= 42/220 + 18/66

= 0.1909 + 0.2727

= 0.4179

In conclusion, the probability is 0.4179.

Learn more about probability on:

brainly.com/question/24756209

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malfutka [58]

Answer:

<em>x = 3.</em>

Step-by-step explanation:

1.  <u><em>Add 2 + 7, and you get 9.</em></u>

2.  <u><em>Now find what 3 multiplied by what equals 9.</em></u>

3. <em><u>3 x 3 = 9.</u></em>

4.  <em><u>Therefore, x = 3.</u></em>

5.  <em><u>3 x 3 - 2 = 7.</u></em>

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3 years ago
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A car purchased for $20,000 depreciates annually at a rate of 8%. The value of the cart years after its purchase is given by the
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3 years ago
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I need help with this one.
Mandarinka [93]

Answer:

T_{n} = \frac{1}{5} T_{n-1} with T₁ = 5000

Step-by-step explanation:

There is a common ratio r between consecutive terms in the sequence, that is

r = \frac{1000}{5000} = \frac{200}{1000} = \frac{40}{200} = \frac{1}{5}

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Here tr = \frac{1}{5} , thus

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3 0
3 years ago
Law of Cosine/Sine problem.
storchak [24]
Either or can be used with any triangle...I personally find the law of sines is often more compact as in this case we can just say;

(sin115)/18=(sin40)/c  (with no need for b or B as would be needed with the law of cosines...)

c=18(sin40)/(sin115)

c≈12.77


4 0
4 years ago
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