15 divided by 3 is 5, so he can buy 5 packs.
Since each pack contains 12 cards, 12x5=60.
Answer:
a) Degree of E = 2
b) Even vertices: B, C, E
Odd vertices : A, D
c) Vertices A, C, and E are adjacent to D
Step-by-step explanation:
a) The degree of a vertex is given by the number of segments that end there, so in the case of vertex E, there are only two segments that connect it, therefore its degree is 2
b) Following the same idea of degree of a vertex, we can find the number of segments that end on each one of the 5 vertices shown and assign to them their degree:
A (3), B (2), C (4), D (3), E (2)
Therefore the odd vertices are: A and D (both of degree 3)
The even vertices are: B, E (both of degree 2, and C (degree 4)
c) the vertices adjacent to vertex D are those connected directly to it via a segment: that is, vertices A, C, and E
Follow PEMDAS
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
(Do these in order)
<u>Answer</u>
6
<u>Explanation</u>
let n be the first even number in the sequence.
The 2nd term = n + 2
3rd term = n + 2 + 2
= n + 4
4th term = n + 4 + 2
= n + 6
The sum of these number = 36.
∴ n + (n +2) + (n + 4) + (n + 6) = 36
4n + 12 = 36
4n = 36 - 12
4n = 24
n = 24/4
= 6
The first term is 6.
The answer = 3x^4+13x^3+20x^2+24x
