Question

Choose the graph that represents the following system of inequalities: y ≤ −3x + 1 y ≤ 1 over 2x + 3 In each graph, the area for f(x) is shaded and labeled A, the area for g(x) is shaded and labeled B, and the area where they have shading in common is labeled AB. Graph of two intersecting lines. Both lines are solid. One line f of x passes through points negative 2, 2 and 0, 3 and is shaded above the line. The other line g of x passes through points 0, 1 and 1, negative 2 and is shaded above the line. Graph of two lines intersecting lines. Both lines are solid. One line g of x passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line f of x passes through points 0, 1 and 1, negative 2 and is shaded above the line. Graph of two intersecting lines. Both lines are solid. One line passes g of x through points negative 2, 2 and 0, 3 and is shaded below the line. The other line f of x passes through points 0, 1 and 1, negative 2 and is shaded below the line.

Answer 1

The graph that represents the inequality has been shown in the attachment.

How to solve for the graph

We have these equations

y ≤ −3x + 1

y ≤ x + 3

We remove the inequality sign from both of these equations

y = −3x + 1

y = x + 3

−3x + 1  = x + 3

such that

x = -0.5

we use this value for x in any of the equations

x + 3 = -0.5 + 3

= 2.5

the point of intersection is at 2.5, -0.5

we test for the origin. 0,0

3x + 1

= 3*0 + 1

= 1

for  x + 3

0+3 = 3

This is 0≤1 and 0≤3

Hence the graph should be shaded to the origin.

Read more on a graph here: brainly.com/question/14030149

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