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AlladinOne [14]
1 year ago
5

Help someone out pls!

Mathematics
1 answer:
likoan [24]1 year ago
6 0

Answer: the answer is D

Step-by-step explanation:V = pi (d/2)^2  *  h

V =  pi  (d^2  / 4)   * h

 h =  4V  /  ( pi  * d^2)       (meters) 

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

7 0
2 years ago
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Answer:

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6 0
3 years ago
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Setler79 [48]
The answer is:

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Tcecarenko [31]

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3 0
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VikaD [51]

Answer:

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Step-by-step explanation:

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Like pi, 'e' is a transcendental number, a number that is not the root of any polynomial with integer coefficients.

3 0
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