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nikdorinn [45]
3 years ago
5

Find The surface area of the pyramid

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

85 ft^2

Step-by-step explanation:

Let us calculate the area of the triangles and the base.

For the triangles, we can use the area formula and get 5 • 3 which is 15. Since there are 4, we multiply it by 4 and get 60.

For the base, we have 5 • 5, which is 25. Adding it together, we get 85.

If you are stuck on how to find surface area, all you have to do is find the area of each side and add.

I hoped this helped!

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Write an absolute value equation that has the given solutions :<br> X = 16 and x = 10
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Hello : 
<span>an absolute value equation is : 
</span><span>|(x-16)(x-10) |=0</span>
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4 years ago
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A paper company ships one 110.4 tons of paper in four trucks if Eachtruck carries the same weight how many tons of
Lerok [7]
Divide total weight by number of trucks:

110.4 / 4 = 27.6 tons per truck
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One weekend, there were 98 pizzas ordered for the sophomore dorm. That weekend 19 customers ordered
vekshin1

Answer:

78 customers

Step-by-step explanation:

The only customers who didn't have pepperoni or sausage was the 20 who ordered with only onions and if you remove those 20 from the 98 total orders you are left with 78 customers who order their pizza with pepperoni or sausage (or both)?

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3 years ago
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The episodes of a TV program are each 40 minutes long.
Hatshy [7]

Answer:

160

Step-by-step explanation:

40*4=160

160 min is also equal to 2 hours and 20 min

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4 0
3 years ago
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The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?
Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

5 0
2 years ago
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