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Anika [276]
2 years ago
9

HELP PLEASE!!!

Mathematics
1 answer:
Phoenix [80]2 years ago
4 0

The atmospheric layer responsible for weather is the troposphere.

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A right-angled triangle has sides of lengths (x+5)cm, (x-3)cm and 9cm. Calculate the value of x
Arturiano [62]

Answer:

x=4.0625 cm

Step-by-step explanation:

The Pythagorean theorem states that the square of the hypotenuse of a right triangle equals the sum of the squares of the two legs.

Not knowing which is the hypotenuse, lets assume that (x+5)cm is the hypotenuse:

(x+5)^2= 9^2+(x-3)^2

(x^2+10x+25)=81+(x^2-6x+9)

x^2+10x+25=81+x^2-6x+9

16x=65

x=4.0625

Checking:

(4.0625+5)^2=9^2+(4.0625-3)^2

82.1289=82.1289

6 0
3 years ago
The sum of two numbers is 3, and twice the larger number is 36 more than three times the smaller number. Find the numbers.
jok3333 [9.3K]

Answer:

x = -6

y = 9

Step-by-step explanation:

The sum of two numbers is 3

x + y = 3

twice the larger number is 36 more than three times the smaller number

2y = 3x + 36

Divide both sides by 2

y = 1.5x + 18

substitute for y in the first equation

x + (1.5x + 18) = 3

2.5x = -15

divide both sides by 2.5

x = -6

Substitute for x in the first equation

-6 + y = 3

y = 9

8 0
3 years ago
Solve for the missing side. Round to the nearest tenth.<br> 10<br> 50°<br> х
s344n2d4d5 [400]

Answer:

15.6

Step-by-step explanation:

8 0
3 years ago
Work out, giving your answer in its simplest form:<br> 2/3 x 3 3/5
kykrilka [37]

Answer: 12/5

Step-by-step explanation:

3 \frac{3}{5}=\frac{18}{5}\\\\\implies \frac{2}{3} \times 3 \frac{3}{5}=\frac{2}{3} \times \frac{18}{5}\\\\=\frac{36}{15}\\\\=\boxed{\frac{12}{5}}

5 0
2 years ago
Given points (r1, u1 ) and (r2, u2) in polar coordinates, obtain a general formula for the distance between them. Simplify it as
sertanlavr [38]

Answer:

  d=\sqrt{r_1^2+r_2^2-2r_1r_2\cos(u_2-u_1)}

Step-by-step explanation:

The Law of Cosines gives an immediate result. No translation to Cartesian coordinates is necessary. That law makes use of the angle between the vectors, u2-u1

  d^2=r_1^2+r_2^2-2r_1r_2\cos(u_2-u_1)\\\\\boxed{d=\sqrt{r_1^2+r_2^2-2r_1r_2\cos(u_2-u_1)}}

6 0
3 years ago
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