Question

A coordinate plane with a line passing through (0, negative 3), (2, 0), and (4, 3).

Answer 1

Answer:

y= (3/2)x-3

Step-by-step explanation:

We need two points to find the equation of a line. Let's take (2,0) and (4, 3).

In the equation y=mx+b, m represents the slope. To find the slope, we can calculate the change in y/change in x. For (2,0) and (4,3), the change in y is 3-0=3 and the change in x is 4-2=2. Therefore, our slope is 3/2.

Then, in the equation y=mx+b, we can plug 3/2 in for m to get y = (3/2)x+b. To find b, we can plug one point in, such as (2.0), to get 0=(3/2)(2) + b, 0=3+b, and b=-3, making our equation

y= (3/2)x-3