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3 years ago

Kareem suffers from a severe liver disease. Which symptoms would you expect to see as a result of this condition

Medicine

1 answer:

aleksandrvk [35]3 years ago

5 0

Answer:

Yellow eyes and skin (jaundice), nausea, abdominal pain and swelling, and swelling of the legs are symptoms for liver disease. :)

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The exercise recommendations to maintain a healthy body weight are GREATER THAN those recommended to reduce risk of chronic disease.

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14) A client is taking a diuretic such as furosemide. When implementing client education, what information should be included

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Carbohydrates of biological importance to elderly and children

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3 years ago

Read 2 more answers

Find the line integral with respect to arc length integral_C (5x +9y)ds, where C is the line segment in the xy-plane with endpoi

mash [69]

Answer:

Explanation:

Given the integral

∫ (5x + 9y) ds

C is the line segment in xy plane with the end points

P = (2,0)

Q = (0, 6)

Let compute the direction of the vector

d = (a, b) = Q - P

(a, b) = (0, 6) - (2,0)

(a, b) = (-2, 6).

A. Now, the equation of line passing through point P(2,0) and Q(0,6) is and have direction d(-2,6) is written as

(x - 2) / -2 = (y - 0) / 6 = t

(x - 2) / -2 = t

x - 2 = -2t

x = 2 - 2t

(y - 0) / 6 = t

y = 6t

Then, the parametric equations of the curve C is

r(t) = (2 - 2t, 6t)

Given that t ranges from t =0 to t = 1

f(x, y) = 5x + 9y

Let compute F(r(t))

From r(t), x = 2-2t and y = 6t

f(r(t)) = 5(2-2t) + 9(6t)

f(r(t) = 10 - 10t + 54t.

f(r(t)) = 10 - 44t.

Thus, the line integral becomes

∫ (5x+9y)ds = ∫f(r(t))•|r'(t)| dt t=0 to 1

Let find |r'(t)|

r(t) = (2 - 2t, 6t)

r'(t) = (-2, 6)

|r'(t)| = √(-2)²+6²

|r'(t)| =√40

So,

∫ (5x+9y)ds = ∫f(r(t))•|r'(t)|

∫f(r(t))•|r'(t)| = ∫(10 - 44t)•√40 dt

∫f(r(t))•|r'(t)| = √40 ∫(10 - 44t) dt

∫f(r(t))•|r'(t)| = √40 (10t - 44t²/2)

∫f(r(t))•|r'(t)| = √40 (10t - 22t²)

t ranges from 0 to 1

Then,

∫f(r(t))•|r'(t)| = √40 (10(1) - 22(1²) - 0 - 0)

∫f(r(t))•|r'(t)| = √40 (10 - 22)

∫f(r(t))•|r'(t)| = √40 × -12

∫f(r(t))•|r'(t)| = -12√40

∫f(r(t))•|r'(t)| = -75.89

So, the line integral of (5x+9y)ds is -75.89

4 0

3 years ago

k 2 Quiz: Histology Integumentary S... Correctly label the parts of an exocrine gland. What kind of gland is this? Secretory ves

defon

Hello! This question is incomplete, but after doing some research on the Internet, I managed to find the picture missing, so I'm attaching it here with the correct answers resolved by me.

The gland in the picture is an APOCRINE GLAND. Apocrine glands are a type of exocrine gland (meaning that they secrete their product onto a duct made of epithelium) that lose their apical portion when they excrete the substance they produce. The product secreted may be contained in secretory vesicles surrounded by the plasma membrane or dissolved in the lost cytoplasm.

This specific apocrine gland appears to be a mammary gland since its product is milk.

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3 years ago