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1 year ago

ICT4AD was meant to modernize the civil service through E-governance implementation.

Computers and Technology

1 answer:

astra-53 [7]1 year ago

7 0

ICT4AD work through E-governance implementation fail as a result of:

Lack of Infrastructure.
High cost of running its affairs as it needs huge public expenditure.
Issues with Privacy and Security and others.

<h3>What is the aim of e-governance?</h3>

The objectives of e-Governance is created so as to lower the level of corruption in the government and to make sure of fast administration of services and information.

Conclusively, It is known to fail due to the reasons given above and if they are worked on, the service would have prospered.

Learn more about civil service from

brainly.com/question/605499

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Modify the code below to do the following:

Kitty [74]

Answer:

The code is appropriately given below with comments for better understanding

Explanation:

#include <linux/init.h>

#include <linux/module.h>

#include <linux/kernel.h>

#include <linux/hash.h>

#include <linux/gcd.h>

#include <asm/param.h>

#include <linux/jiffies.h>

/* This function is called when the module is loaded. */

static int simple_init(void)

{

printk(KERN_INFO "Loading Module\n");

printk(KERN_INFO "These are the HZ: %d\n", HZ);

printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

printk(KERN_INFO "Golden Ratio is: %lu\n", GOLDEN_RATIO_PRIME);

return 0;

}

/* This function is called when the module is removed. */

static void simple_exit(void) {

printk(KERN_INFO "Removing Module");

unsigned long a = gcd(3300, 24);

printk(KERN_INFO "Greatest Common Denominator between 3,300 and 24 is: %lu\n", a);

printk(KERN_INFO "These are the jiffies: %lu\n", jiffies);

}

/* Macros for registering module entry and exit points. */

module_init( simple_init );

module_exit( simple_exit );

MODULE_LICENSE("GPL");

MODULE_DESCRIPTION("Simple Module");

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3 years ago

The windows troubleshooting utility that identifies and eliminates nonessential files is called _____.

Virty [35]

I think it is Defragment

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3 years ago

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What command displays detail information about the OSPF interfaces, including the authentication method?

statuscvo [17]

<span>The answer is Show IP OSPF interface

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3 years ago

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A technician, joe, has replaced a faulty 500 gb hard drive in a pc system with a 1 tb hard drive. however, after the replacement

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The best possible solution for the technician to do is to go into the disk management and find out what exactly is going on. The technician should check whether there is partition that has unallocated space. It is 100% the case that the rest of the 500 GB is in the unallocated space.

The techie need to grow his partition. Possible option for a scenario like this is delete the unallocated 500 GB space using NTFS. He can then recreate the available 500 GB free space as 1TB partition.

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3 years ago

Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.

arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

public static void main(String[] args)

{

Scanner SC = new Scanner(System.in);

RomantoDecimal r = new RomantoDecimal();

System.out.println("Enter a Roman number :");

// INPUT A ROMAN NUMBER

String rNum = SC.next();

// CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

r.convertToDecimal(rNum);

}

// M=1000, D=500, C=100, L=50, X=10, V=5, I=1

public void convertToDecimal(String roamNo)

{

int number = 0;

// TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

for (int i = roamNo.length() - 1; i >= 0; i--)

{

// FIND OUT WHETHER IT IS 'M' OR NOT

if (roamNo.charAt(i) == 'M')

{

if (i != 0)

{ // CHECK WHETHER THERE IS C BEFORE M

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 900;

i--;

continue;

}

number = number + 1000;

}

// FIND OUT WHETHER IT IS 'D' OR NOT

else if (roamNo.charAt(i) == 'D')

{

if (i != 0)

{

// CHECK WHETHER THERE IS C BEFORE D

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 400;

i--;

continue;

}

number = number + 500;

}

// FIND OUT WHETHER IT IS 'C' OR NOT

else if (roamNo.charAt(i) == 'C')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'X')

{

number = number + 90;

i--;

continue;

}

number = number + 100;

}

else if (roamNo.charAt(i) == 'L')

{

if (i != 0)

{

if (roamNo.charAt(i) == 'X')

{

number = number + 40;

i--;

continue;

}

number = number + 50;

}

// FIND OUT WHETHER IT IS 'X' OR NOT

else if (roamNo.charAt(i) == 'X')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 9;

i--;

continue;

}

number = number + 10;

}

// FIND OUT WHETHER IT IS 'V' OR NOT

else if (roamNo.charAt(i) == 'V')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 4;

i--;

continue;

}

number = number + 5;

}

else // FIND OUT WHETHER IT IS 'I' OR NOT

{

number = number + 1;

}

}// end for loop

System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

}

3 0

3 years ago