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PIT_PIT [208]
3 years ago
14

How does beamforming improve network service?

Computers and Technology
1 answer:
fenix001 [56]3 years ago
7 0

Beamforming can improve network service by using device locations to better target service signals.

This is because, beamforming helps to deliver higher signal quality to the target receiver.

<h3>What is beamforming?</h3>

beamforming can be regarded as application of different radiating elements that is transmitting the same signal.

This signal is usually identical in wavelength and phase, and  by reinforcing the waves in a specific direction the goal can be acheived.

Learn more about beamforming at:

brainly.com/question/12809344

You might be interested in
Is there apps/ websites like brainly?
Virty [35]

Answer:

Mathpix Snip, Socratic, Microsoft Math Solver....etc.

Explanation:

Hope this helps! :)

6 0
3 years ago
Read 2 more answers
Implement a sublinear running time complexity recursive function in Java public static long exponentiation (long x, int n) to ca
Archy [21]

Answer:

Following are the code block in the Java Programming Language.

//define recursive function

public static long exponentiation(long x, int n) {

//check the integer variable is equal to the 0.

if (x == 0) {

//then, return 1

return 1;

}

//Otherwise, set else

else {

//set long data type variable

long q = exponentiation(x, n/2);

q *= q;

//check if the remainder is 1

if (n % 2 == 1) {

q *= x;

}

//return the variable

return q;

}

}

Explanation:

<u>Following are the description of the code block</u>.

  • Firstly, we define the long data type recursive function.
  • Then, set the if conditional statement and return the value 1.
  • Otherwise, set the long data type variable 'q' that sore the output of the recursive function.
  • Set the if conditional statement and check that the remainder is 1 and return the variable 'q'.
8 0
4 years ago
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
The rules and guidelines for appropriate computer mediated communication are called?
irinina [24]
<span>The rules and guidelines for appropriate computer mediated communication are called netiquette. 
It is a blend of two words: net (from Internet) and etiquette, or the appropriate behavior. 
</span>
4 0
4 years ago
Planet X is a terrestrial planet in our solar system. It has 21% oxygen in its atmosphere. Humans can walk on this planet withou
Arte-miy333 [17]
Based on the given description above, the planet that is being described would be planet EARTH. It is the only planet where humans can walk without the aid of a space suit, and the only planet that can provide humans the necessary oxygen to survive. Hope this answers that question.
8 0
3 years ago
Read 2 more answers
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