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sladkih [1.3K]
3 years ago
14

Evaluate −6a^3+8a^2+8a+1, when a=5.

Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

-509

Step-by-step explanation:

1. Subsitute 5 for a in the expression.  -6(5)^3+8(5)^2+8(5)+1

2. -6(125)+8(25)+40+1

3. -750+200+41

4. -509

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When y is 4, p is 0.5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equation
Radda [10]
<h3><u>Question:</u></h3>

When y is 4, p is 0.5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equation models the situation?

xpmy=8

xy/pm=8

xpm/y=0.5

x/pmy=0.5

<h3><u>Answer:</u></h3>

The equation models the situation is \frac{x y}{p m}=8

<h3><u>Solution:</u></h3>

Given that  

x is 2, y is 4, p is 0.5, and m is 2

x varies directly with the product of p and m

x varies inversely with y

\text {Product of } p \text { and } m=p \times m=p m

x varies directly with the product of p and m

=>x \propto p m ---- eqn 1

As x varies inversely with y,

=>x \propto \frac{1}{y}   ----- eqn 2

From (1) and 2, we can say that

x \propto \frac{p m}{y}

\Rightarrow x=k \frac{p m}{y}

where k is constant of proportionality

\Rightarrow \frac{x y}{p m}=k   ---- eqn 3

On substituting given values of x = 2, y = 4, p = 0.5 and m= 2 in eqn (3) we get

\frac{x y}{p m}=\frac{2 \times 4}{0.5 \times 2}=k

\begin{array}{l}{\frac{x y}{p m}=\frac{8}{1}=k} \\\\ {=>\frac{x y}{p m}=8}\end{array}

Hence correct option is second that is \frac{x y}{p m}=8

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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kiruha [24]
I think this is right

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Answer:

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