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Nitella [24]
2 years ago
7

Please help!! Katherine O'Donnell obtained a personal loan of $1,800 at 10% for 12 months. The monthly payment is $165.00.

Mathematics
1 answer:
ololo11 [35]2 years ago
5 0

Answer:

  $1650

Step-by-step explanation:

Each payment is applied first to the amount of interest that is due, then to the remaining principal.

__

For the first monthly payment, the interest due is ...

  I = Prt = $1800(0.10)(1/12) = $15.00

So, the amount of the payment that gets applied to the principal is ...

  payment - interest = $165 -15 = $150

The new balance is ...

  $1800 -150 = $1650.00 . . . . new principal after the first payment

__

The attachment shows the balance after each payment. Each interest amount is rounded to cents. The negative balance after the last payment is the amount of excess that last payment represents.

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A city doubles its size every 12 years. If the population is currently 500,000, what will the population be in 24 years?
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Marcus has earned 353 out of 400 points (88% or B+) in Math class. He needs 90% to earn an A-. There is one test left worth 100
aleksklad [387]

Answer:

97

Step-by-step explanation:

Marcus is aiming for an A- (90-94 percent). The question states that there is another test awaiting that is worth 100 points. In order to find the answer to the question, you need to:

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2.) Use the answer choices and add it to 353.

88 + 353 = 441

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Since Marcus is aiming for an A-, we can conclude that obtaining 97 points will help Marcus achieve an A-.

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How do you multiply 23.50*23.74
Mamont248 [21]

Answer:

557.89

Step-by-step explanation:

Download photomath on Appstore it'll help you explain. but basically you multiply each digit at the bottom to the whole number on the top

    23.50

<u>x   </u><u>23.74</u>

       940     ====== 23.50 multiply to 4

    16450     ====== 23.50 multiply to 7

    70500    ====== 23.50 multiply to 3

<u>+   470000   </u> ====== 23.50 multiply to 2

   557.890    ====== Add all the numbers together, move the decimal sign down to align with the result

<u />

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