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vekshin1
3 years ago
10

Need a bit of help with this​

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Answer:

<h2>∠HFG = 115°</h2>

Step-by-step explanation:

∠JFG + ∠HJF = 180° <em>[Adjacent angles of parallelogram are supplementary] </em>

<em>∠</em>JFG = 65°

=> 65° + ∠HJF = 180°

=> ∠HFG = 180° - 65°

=> ∠HFG = 115°

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Triangle P R Q is shown. Angle R P Q is 39 degrees. The length of P R is 6, the length of R Q is p, and the length of P Q is 8.
KATRIN_1 [288]

According to law of cosines the length of RQ can be written as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.

A length of the triangle can be written as according to law of cosines if sides are given and one angle is a^{2} =b^{2} +c^{2} -2bccos(A)

We have to just put the values in the above equation.

as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.

Hence the side can be written as according to law of cosines if the angle is 39 degrees is  as p^{2} =6^{2} +8^{2} -2*6*8cos(39).

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

7 0
1 year ago
Need help fastt plss will give brainliest too who is corect plssss helppp
ehidna [41]

Answer:

0-5

Step-by-step explanation:

The Range Is 0-5 Atleast what i understand Gl Passing!

5 0
3 years ago
Read 2 more answers
BRAINLIESTTT ASAP! PLEASE HELP ME :)
kherson [118]

Answer:

b. \displaystyle 225y^2 + 150xy + 100x^2 = 225y^2 + 150xy + 100x^2

a. \displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2

Step-by-step explanation:

b. \displaystyle 225y^2 + 150xy + 100x^2 = 225y^2 + 150xy + 100x^2

a. \displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2

The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.

I am joyous to assist you anytime.

6 0
3 years ago
Find two matrices A and B such that 2A-3B= [5 0
amm1812

The easy answer: If, say, B is the zero matrix, i.e.

B=\begin{bmatrix}0&0\\0&0\end{bmatrix}

then

2A=\begin{bmatrix}5&0\\-1&2\end{bmatrix}\implies A=\begin{bmatrix}\dfrac52&0\\\\-\dfrac12&1\end{bmatrix}

3 0
3 years ago
1. x + 2x - 1 = 38<br> Inverse operation
Lena [83]

Answer:

x=13

Step-by-step explanation:

First, you add the x's together: 2x+x=3x

Now you have:3x-1=38

Add 1 to both sides: 3x=39

1 cancel on the left side of the equation

Divide 3 on both sides: x=39/3

3 cancels on the left side and 39 divided by 3 is 13:

x=13

Hope this helps!

6 0
2 years ago
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