Use natural logrithms to solve 6e^(2x) – 9 = 23

Mathematics

1 answer:

Wittaler [7]3 years ago

7 0

Hello :
 6e^(2x) – 9 = 23
 6e^(2x) = 32
e^(2x) = 32/6 =16/3
2x = ln(16/3/
x = (1/2) ln(16/3)

You might be interested in

PLZ HELPPPPPPPP

Lorico [155]

Answer:

Think

Step-by-step explanation:

Think its 2.

6 0

3 years ago

Jill got 36 out of 40 questions correct on her test. What percent of her test did she get correct?

ale4655 [162]

Answer:

36 percent I think ya

Step-by-step explanation:

I think I should know this

5 0

3 years ago

Read 2 more answers

(3 + 4i) - (8 -5i) Write answer in standard form a +bi Group of answer choices

Anton [14]

Answer:

$A=-5+9i$

Step-by-step explanation:

$\left(3+4i\right)-\left(8-5i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\\\=\left(3-8\right)+\left(4+5\right)i\\3-8=-5\\4+5=9\\\\=-5+9i$

5 0

3 years ago

The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. What are the coordinates of the vertex of the grap

Studentka2010 [4]

Answer:

D) $(-2,-9)$

Step-by-step explanation:

Vertex Form of a Vertical Parabola:

$y=a(x-h)^2+k$

Vertex -> $(h,k)$

Axis of Symmetry -> $x=h$

Vertical Scale Factor -> $a$

To turn $f(x)=x^2+4x-5$ into vertex form, we need to complete the square on the right side
Therefore, if $f(x)=0$ , then $0+9=x^2+4x-5+9$ completes the square on the right side
This becomes $9=(x+2)^2$
This means that our function in vertex form is $f(x)=(x+2)^2-9$