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Serggg [28]
3 years ago
13

Use natural logrithms to solve 6e^(2x) – 9 = 23

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0
Hello : 
<span> 6e^(2x) – 9 = 23
</span><span> 6e^(2x)  = 32
</span>e^(2x)  = 32/6 =16/3
2x = ln(16/3/
 x = (1/2) ln(16/3)


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Answer:

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<em>\sqrt{50}</em>

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You have use the Pythagorean Theorem a^{2} + b^{2} = c^{2}

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x^{5} + x^{5} = c^{2} \\25 + 25 = c^{2} \\50= c^{2} \\\sqrt{50} = \sqrt{c^{2} } \\\sqrt{50} = c\\

extra notes

  • If you didn't know, you cancel exponents with roots.

So the c^{2} is cancled by aka \sqrt{c}

  • You can't simplify \sqrt{50} so it stays like that

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