Question

3^−1⋅(4⋅6)⋅2^−3 Enter your answer in the box.

Answer 1

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

and $a^{-1}=\dfrac{1}{a};\ a^{-n}=\dfrac{1}{a^3}$

$3^{-1}\cdot(4\cdot6)\cdot2^{-3}=\dfrac{1}{3}\cdot24\cdot\dfrac{1}{2^3}=\dfrac{24}{3}\cdot\dfrac{1}{8}=\not8^1\cdot\dfrac{1}{\not8_1}=1$