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Leni [432]
2 years ago
13

Need help please math............

Mathematics
1 answer:
Vsevolod [243]2 years ago
8 0

Answer:

9\frac{52}{69}  - 1 \frac{29}{50}

\frac{673}{69}  -   \frac{79}{50}

\frac{673}{69} to  \: the \: nearest \: whole \: number \: is \: 10

\frac{79}{50} to \: the \: nearest \: whole \: number \: is \: 2

> >  > 10 - 2 = 8

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One tablet costs $249.00 and a company needs to buy k tablets. What is the relationship between the total cost, C, and the numbe
PtichkaEL [24]

Answer:

b

Step-by-step explanation:

8 0
4 years ago
★write the pair of integer in which multiplication is -45 and difference is 12.
vladimir1956 [14]

Answer:

(3 and 15)

Step-by-step explanation:

If the product of both of these two numbers needs to be a negative 45 then there are no pair of integers that comply with both requirements.

If the multiplication in the question is wrong and it is a positive 45 then the pair of integers that would comply with these requirements would be (3 and 15). Multiplying this pair together would give you 45 and the difference between them is also 12 meaning it complies with both requirements that were asked for in the question.

5 0
3 years ago
Factorise
dlinn [17]

9514 1404 393

Answer:

  a) 7(3x +7)

  b) y(3y -1)

  c) 4x^2(2 +x)

  d) 2s^2t^2(12s +5t^2)

Step-by-step explanation:

These are factored by finding the greatest common factor of the given terms. Generally, that can be found by looking at the factors and finding the largest that is common to all terms.

__

a) 21 = 7·3; 49 = 7·7. The GCF is 7. Factoring that out gives ...

  7(3x +7)

__

b) y is the only factor common to both terms.

  y(3y -1)

__

c) 4 and x^2 are factors common to both terms, assuming the second term is 4x^3.

  4x^2(2 +x)

__

d) 10 = 2·5; 24 = 2·12; the factors s^3 and s^2 share a factor of s^2; the terms t^2 and t^4 share a factor of t^2.

  2s^2t^2(12s +5t^2)

5 0
3 years ago
PLZZZ JUST HELPP MEE BRAUNLIESTTTT
Kay [80]

Answer:

question1. x+7=12

question9. n+5

question8. x/3

5 0
3 years ago
F(x)=x^2-3x+7 and g(x)=x+3 solve f(x)=g(x)
grandymaker [24]

For this case we have the following functions:

f (x) = x ^ 2-3x + 7\\g (x) = x + 3

Equalizing we have:

x ^ 2-3x + 7 = x + 3\\x ^ 2-3x-x + 7-3 = 0\\x ^ 2-4x + 4 = 0

To solve we factorize, that is, we look for two numbers that when multiplied give a result of 4 and when added together give a result of -4. These numbers are -2 and -2.

-2-2 = -4\\(-2) * (- 2) = 4

Thus, we have:

(x-2) (x-2) = 0\\(x-2) ^ 2 = 0

So, the solution isx = 2

Answer:

x=2

8 0
4 years ago
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