Answer:
244 cm
Step-by-step explanation:
Answer:
Step-by-step explanation:
We need to solve the quadratic equation
6 = x^2 -10x
Rearranging we get,
x^2-10x-6=0
Using quadratic formula to solve the quadratic equation
a= 1, b =-10 and c=6
Putting values in the quadratic formula
So, 
Answer:
x>5
Step-by-step explanation:
-3(2x+5)<-45
2x+5<-45/-3
2x+5<15
2x<15-5
2x<10
x<10/2
x<5
x>5
Two negatives <em>do not </em>equal a positive when adding. If you're in debt and you add more debt, does that get you out of debt?
Two negatives <em>do </em>equal a positive when you're multiplying them together though. This makes sense if you imagine multiplication as squishing or stretching a particular number on the number line. For example, imagine multiplying 2 x 1/2 as <em>squishing </em>the number 2 two times closer to 0. When you multiply 2 by a negative number, say, -1, you squish it so far down that you <em>flip it to the negative side of the number line</em>, bringing it to -2. You can imagine a similar thing happening if you multiply a number like -4 by -2. You squish -4 down to zero, and then <em>flip it to the positive side</em> and stretch it by a factor of 2, bringing it to 8.
Try this option:
common equation for line is y=kx+b, where k=tgα, b-number.
Rule: if y||y₁, then k=k₁.
It means that according to given conditions y₁=k₁x+b₁ ⇒ y₁=6x+b₁.
answer: y₁=6x+b₁
