2 years ago

Your friend says that it is impossible for the circumcenter of a triangle to

1 answer:

8 0

Answer:

no because he is STUPlD

Step-by-step explanation:

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Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

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3 years ago

olga2289 [7]

Answer:

OK 825/1000 That is the answer.

8 0

3 years ago

Slav-nsk [51]

May I please ask,Where is the Mathematic problem that I may solve. ;)

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3 years ago

ArbitrLikvidat [17]

There’s not graph so if you could provide a graph

7 0

3 years ago

NikAS [45]

Answer:

18ft

Step-by-step explanation:

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3 years ago