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2 years ago

Two numbers whose sum is 29 and their difference is 15

Mathematics

1 answer:

n200080 [17]2 years ago

6 0

Answer:

22 and 7

Step-by-step explanation:

Let x and y be the two numbers we are looking for:

The statement “their sum is 29” means x + y = 29

The statement “their difference is 15” means x - y = 15

we get this system:

x + y = 29 (1)

x - y = 15 (2)

Let’s solve it :

(1) + (2) ⇒ x + y + x - y = 29 + 15 ⇒ 2x = 44 ⇒ x = 44/2 = 22

Now we replace x by 22 in equation (1) :

22 + y = 29 ⇒ y = 29 - 22 = 7

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The diameter of a cookie is 2 inches. If π = 3.14, what is the area of the cookie, rounded to the nearest tenth?

insens350 [35]

Answer:

3.1 inches

Step-by-step explanation:

Area of the cookie =Pi r^2

Pi = 3.14

Diameter = 2inches

Radius r = diameter/2 = 2/2

= 1

Therefore

Area = 3.14 x 1^2

= 3.14 x 1 x 1

= 3.1 inches

3 0

3 years ago

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

6 0

3 years ago

PLS HELP ME 50 POINTS!!!!! I NEED AN ANSWER ASAP!!!!!!

Sholpan [36]

Answer:

They went up 16 levels.

Step-by-step explanation:

You can find that by finding the distance from -2 to 14.
To find the distance from two numbers, $a$ and $b$ , we can substitute both in the formula $d = |b - a|$ , where d is the distance between them.

$d = |14 - (-2)| \to |14 + 2|\to|16|\to16$

4 0

1 year ago

Read 2 more answers

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is: