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Ad libitum [116K]
1 year ago
14

Solve the inequality for x and identify the graph of its solution.

Mathematics
1 answer:
bixtya [17]1 year ago
5 0

Answer:

D

Step-by-step explanation:

^^^

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3 is 13
4 is 18
5 is 20
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Find the explicit formula for the given sequence.
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Option a.) an = -4(-3)^(n-1)

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if 1/4 of a gallon of paint is needed to paint 2/3 of a fence, how many gallons are needed to paint the entire fence? site:socra
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\bf \begin{array}{ccll} \stackrel{paint}{gallons}&fence\\ \cline{1-2} \\\frac{1}{4}&\frac{2}{3}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{1}{4}~~}{x}=\cfrac{~~\frac{2}{3}~~}{1}\implies \cfrac{~~\frac{1}{4}~~}{\frac{x}{1}}=\cfrac{2}{3}\implies \cfrac{1}{4}\cdot \cfrac{1}{x}=\cfrac{2}{3} \\\\\\ \cfrac{1}{4x}=\cfrac{2}{3}\implies 3=8x\implies \cfrac{3}{8}=x

7 0
3 years ago
Read 2 more answers
Rodney bought a 50 pound bag of dog food. HIS dog ate 2/5 of the food in the first mon th and 2/10 of the food in the second mon
NeTakaya

Answer:

20 lbs

Step-by-step explanation:

2/5ths of the food would be 20 pounds because:

2/5 * 50 = 20

2/10ths of the food would be 10 pounds because:

2/10 * 50 = 10

If we add those two together, we would get the total amount that the dog ate, which would be 30 pounds. SInce the dog ate 30 pounds of food out of the 50 pounds, there would be 20 pounds left in the bag at the end of two months:

50- ( 20+ 10) = 20

4 0
3 years ago
An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.
SCORPION-xisa [38]

Answer:

(a)See below

(b)I) 0.125  (ii)0.828125   (iii)0.234375   (iv) 0.625   (v)0.65625

Step-by-step explanation:

When an  8-sided die is rolled twice, the sample space is the set of all possible pairs (a,b) where a is the 1st outcome and b is the 2nd outcome.

The sample space is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]

<u>PART A</u>

The sample space of the product a*b of each pair forms the required possibility diagram.

This is given as:  

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

<u>PART B</u>

I) A prime number

The number of products that gives prime numbers = 8  

The probability that the product is a prime number

=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125

ii) Not a perfect square  

Number of products that results in perfect squares =11

The probability that the product is not a perfect square

=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125

iii) A multiple of 5  

Number of products that are multiples of 5=15

 The probability that the product is a multiple of 5

=\dfrac{15}{64}\\=0.234375

iv) Less than or equal to 21

Number of products which are less than or equal to 21=40

 The probability that the product less than or equal to 21

=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625

v) Divisible by 4 or 6

Number of products divisible by 4 or 6= 42

 The probability that the product is divisible by 4 or 6

=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625

8 0
2 years ago
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