All categories

1 year ago

Solve the following inequality. 2P - 3 > P + 6

Mathematics

2 answers:

zzz [600]1 year ago

8 0

<h3>Hi There!</h3>

Here's how we solve inequalities:

Given:
2p-3>p+6
To Find: p

<h3>Solution:</h3>

Move all the p's to the left, using the <em>opposite operation</em>:
2p-p-3>6
Move all the numbers to the right, using the opposite operation:
2p-p>6+3
Combine Like Terms:
p>9

<h3>Thus, all the values of p greater than 9 will make the inequality true.</h3>

Final Answer: p>9

<h3>Hope it helps!</h3>

<em>Have an awesome day!</em>

<em /> $\huge\text{\bf{TheStarryNights\::D}}$

WITCHER [35]1 year ago

7 0

Answer:

P > 9

Step-by-step explanation:

first, you add 3 to both sides,

2p > P + 9

then subtracts P from both sides,

P > 9

your final answer is P > 9

Hope this helps! :)

You might be interested in

Help ASAP please! I dont understand.

igomit [66]

All of the box numbers are decide by the bottom numbers. Ex: 3+4=7, the top box is seven above 3 and 4. So you would add 16 and 17 which is 33. The answer is 33.

7 0

2 years ago

Read 2 more answers

Suppose you buy a 1.25 pound package f ham at $5.20 per pound what fraction of a pound did you buy

Andrew [12]

1 1/4

Hope it helps :)

8 0

3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

8. Given: PQR and TSR are right triangles,

rewona [7]

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are scalene, right angled, isosceles, equilateral.

A right angled triangle is a triangle with one angle equals to 90°.

Statement Reason

∠PQR = ∠RST Given. ∠PQR = ∠RST = 90° (definition for right

angle triangle.

PQ = ST Given

PR ≅ RT Since R is the midpoint of PT, hence PR = RT

ΔPQR ≅ ΔTSR Side-angle-side triangle congruence theorem.

the Side-angle-side triangle congruence theorem

states that if two sides and an included angle of

one triangle is equal to two sides and an included

angle of another triangle, then the two triangles

are congruent. PQ=ST, PR = RT and ∠PQR = ∠TSR

3 0

2 years ago

A train left a station a station at noon going 40mph. A second train left at 3 p.m. going 60mph. At what time will the second tr

Sati [7]

Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.

But the time traveled will be different .

Let us say the two trains meet at time t ,

Distance = speed * time

Distance traveled by first train = 40 t

Since second train is leaving after three hours , so

Distance traveled by second train = 60(t-3)

As discussed earlier, distance traveled will be same, so

$40t =60(t-3)$