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2 years ago

Solve the following inequality. 2P - 3 > P + 6

Mathematics

2 answers:

zzz [600]2 years ago

8 0

<h3>Hi There!</h3>

Here's how we solve inequalities:

Given:
2p-3>p+6
To Find: p

<h3>Solution:</h3>

Move all the p's to the left, using the <em>opposite operation</em>:
2p-p-3>6
Move all the numbers to the right, using the opposite operation:
2p-p>6+3
Combine Like Terms:
p>9

<h3>Thus, all the values of p greater than 9 will make the inequality true.</h3>

Final Answer: p>9

<h3>Hope it helps!</h3>

<em>Have an awesome day!</em>

<em /> $\huge\text{\bf{TheStarryNights\::D}}$

WITCHER [35]2 years ago

7 0

Answer:

P > 9

Step-by-step explanation:

first, you add 3 to both sides,

2p > P + 9

then subtracts P from both sides,

P > 9

your final answer is P > 9

Hope this helps! :)

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3 years ago

the ages of two friends Sunaina and Tanish are differ by 2 years sunaina's father is twice as old as Sunaina and Tanisha is twic

nikklg [1K]

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Let T represent Tanish's age.

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3 years ago

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3 years ago

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3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

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3 years ago