Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
Answer:
Explanation:
Oxygen gas and water must be present for iron to rust.
A region of the metal’s surface serves as the anode, where oxidation
occurs:
Fe(s) → Fe²⁺ (aq) + 2 e⁻
The electrons given up by iron reduce atmospheric oxygen to water at the cathode, which is another region of the same metal’s surface:
O₂ (g) + 4H⁺ (aq) + 4 e⁻ → 2 H₂O (l)
The overall redox reaction is:
2 Fe(s) + O₂(g) → 4H⁺(aq) + 2Fe²⁺ (aq) + 2 H₂O(l)
The Fe²⁺ ions formed at the anode are further oxidized by oxygen:
4 Fe²⁺ (aq) + O₂(g) 1 (4 + 2x) H₂O (l) → 2 Fe₂O₃ . xH₂O(s) + 8 H⁺(aq)
This hydrated form of iron(III) oxide is known as rust. The amount of water associated with the iron oxide varies, so we represent the formula as 2 Fe₂O₃ . xH₂O.
On way to test a mineral is to break it and see how many directions of Cleavage it has
Each on diverged from the common ancestor and has its own accumulated mutations. If they have six differences each it would be 10,000 years per one mistake giving you a total of 60,000 years ago.
