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1 year ago

Evaluate (−3) ^−3

Mathematics

1 answer:

Fynjy0 [20]1 year ago

4 0

<h3>Answer:</h3>

-1/27

<h3>Solution:</h3>

If we have a number to a negative power, we flip the number over, like so:
$-3- > \displaystyle\frac{1}{(-3)^3}$
Simplify:
$\displaystyle\frac{1}{-27} =-\frac{1}{27}$

Hope it helps.

Do comment if you have any query.

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Does anyone know about this question I give brainless If you answer this correctly

xxTIMURxx [149]

Answer:

Side x = 2.12132 = 3√2/2

Step-by-step explanation:

I used a triangle calculator to find side x

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3 years ago

A 12 ounce Starbucks latte costs $3.36. What is the constant of proportionality that relates the cost in dollars, y, to the numb

bazaltina [42]

Answer:

Y = X times 0.28

Step-by-step explanation:

1. You set it up as a proportionality

12/1 and 3.36/x

The x stands for how much money it takes to get 1 ounce

2. You do the old man line.

12 times x = 3.36 times 1

12x = 3.36

3. Now you divide 3.36 by 12

3.36 divided by 12

.28

4. You insert 0.28 into the problem

12 times 0.28 = 3.36

X = 0.28

So 1 ounce costs $0.28

So Y = X times 0.28

5 0

2 years ago

Read 2 more answers

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

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3 years ago

For this isosceles triangle, find the measure of angles h and m.

Genrish500 [490]

Hello,

x + x + 128° = 180°

2x + 128° = 180°

2x = 180° - 128° = 52°

x = 52° / 2 = 26°

7 0

3 years ago

In expansion of (2x+1)(x^2+px+4), the coefficient of x is twice the coefficient of x^2.

Brilliant_brown [7]

You're probably supposed to find the value of p and not x, which is impossible to do.

Expanding gives

$(2x+1)(x^2+px+4)=2x^3+(1+2p)x^2+(8+p)x+4$

We're told that

$8+p=2(1+2p)$

which we can use to solve for p:

$8+p=2+4p$

$6=3p$

$\boxed{p=2}$

7 0

3 years ago