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yarga [219]
3 years ago
12

Find the midpoint of the line segment with the endpoints (10,2) and (-6,-6)

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

(2,-2)

Step-by-step explanation:

Using the midpoint formula:

m=\left( \dfrac{10-6}{2},\dfrac{2-6}{2} \right)=\left( \dfrac{4}{2}, \dfrac{-4}{2}\right)=(2,-2)

Hope this helps!

Fudgin [204]3 years ago
5 0

Answer:

The midpoint is (2,-2)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates together and divide by 2

(10+-6)/2 = 4/2 =2

To find the y coordinate of the midpoint, add the y coordinates together and divide by 2

(2+-6)/2 = -4/2 =-2

The midpoint is (2,-2)

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Answer:

5:10

6 (-2,0)

7 (-5,6)

8 (5,3)

9 No, ab=8 CD=6

Step-by-step explanation:

4 0
3 years ago
Write 3.7 as a mixed number explain
frosja888 [35]
3 and 7/10 or 37/10
Just look up mixed numbers
You must convert it into a fraction so it will be a mixed number
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3 0
2 years ago
Read 2 more answers
Jill had $125 to spend at the mall. She spent 27% of that money on a pair of shoes. Jill spent $___ on the shoes.
zaharov [31]
You need to find what 27% of $125 is.
To find a percent of a number, multiply the percent by the number.

27% of $125 =

= 27% * $125

= 0.27 * $125

= $33.75

Answer: Jill spent $33.75 on the shoes.
4 0
3 years ago
A programmer plans to develop a new software system. In planning for the operating system that he will​ use, he needs to estimat
Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A.  ​Yes, using the additional survey information from part​ (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

For this problem, we consider that we want it to be within 4%.

Item a:

  • The sample size is <u>n for which M = 0.04.</u>
  • There is no estimate, hence \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2

n = 600.25

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is \pi = 0.96, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}

\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2

n = 92.2

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to \pi = 0.5, the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151  

8 0
2 years ago
P is the point with coordinates (3, 1)
earnstyle [38]

Answer:

c will be the answer mark me brainliest

3 0
3 years ago
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