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3 years ago

Find the midpoint of the line segment with the endpoints (10,2) and (-6,-6)

Mathematics

2 answers:

slega [8]3 years ago

8 0

Answer:

(2,-2)

Step-by-step explanation:

Using the midpoint formula:

$m=\left( \dfrac{10-6}{2},\dfrac{2-6}{2} \right)=\left( \dfrac{4}{2}, \dfrac{-4}{2}\right)=(2,-2)$

Hope this helps!

Fudgin [204]3 years ago

5 0

Answer:

The midpoint is (2,-2)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates together and divide by 2

(10+-6)/2 = 4/2 =2

To find the y coordinate of the midpoint, add the y coordinates together and divide by 2

(2+-6)/2 = -4/2 =-2

The midpoint is (2,-2)

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3 years ago

Read 2 more answers

In December, the average total rainfall in all the deserts together is 0.89 mm. Explain how to use the fiqures from the table to

maw [93]

I know this is late but I can still help answer this....

So we know that in December all the deserts altogether had 0.89 mm of rainfall. Now the chart that you have seems to represent the rainfall in August, so we would need to use addition.
0.19 + 0.17 + 0.1 + 0.24 = 0.70 mm
The rainfall altogether would be 0.70 mm in August. Now we compare the difference, we would need to subtract 0.89 mm (December) with 0.70 mm (August).
0.89 - 0.70 = 0.19 mm
There the difference between the two would be 0.19 mm.

Hope this helps!

6 0

3 years ago

In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer

stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = percentage of patients stop smoking when given sustained care.

So, Null Hypothesis, $H_0$ : p = 80% {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, $H_A$ : p $\neq$ 80% {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here One-sample z test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of patients who stop smoking when given sustained care = 80.2%

n = sample of patients = 192

So, the test statistics = $\frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }$

= 0.07

The value of z test statistics is 0.07.

Also, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.07) = 1 - P(Z $\leq$ 0.07)

= 1 - 0.52790 = 0.4721

Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0

3 years ago