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zhannawk [14.2K]
3 years ago
11

Choose the correct description of the graph of the compound inequality: x − 2 > −3 and 3x less than or equal to 12

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0

A number line with an open circle -1, closed circle on 4 and shading in between.

Is the answer.

Hope this helps....

STALIN [3.7K]3 years ago
4 0
<span>X - 2 > -3 x > -3 + 2 x > -1 A number line with an open circle -1, closed circle on 4 and shading in between.,when dividing/multiplying by a negative, the inequality sign changes. An open circle is used when there is no equal sign involved. A closed circle is used when there is an equal sign involved. If it is greater then, shading goes to the right. If it is less then, shading goes to the left</span>
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1/4 + n = 2/3 *using the inverse operation*
Virty [35]

Answer:

Exact Form:

n = 5 /12

Decimal Form:

n= 0.41 6



hope this helps.

sorry if it doesn't

6 0
3 years ago
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Can someone help me with this? Please
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Answer:

What? help you with what

Step-by-step explanation:

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Overnight the temperature dropped 1.3 degrees every hour how many hours did it take the temperature to drop 7.8 degrees
antiseptic1488 [7]
6 and 1/2 hours in total. divide 7.8 by 1.3
7 0
3 years ago
Write a number that has four digits with the same number in all places such as 4444 circle the digit with the greatest value und
joja [24]
For example you can take the number 7 7 7 7

(7)77{7}

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4 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
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