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labwork [276]
2 years ago
14

Which linear function has the greatest rate of change?​

Mathematics
2 answers:
matrenka [14]2 years ago
8 0
The answer is C 252 rate of change
Lemur [1.5K]2 years ago
8 0

Answer:

D

Step-by-step explanation:

The rate of chnage is the same as the slope.

Slope is x/y. How many y increases/decreases per increase of 1 x

slope for A is

2/500 every 2 x increase, y goes up by 500.

slope for B is

2/500 every 2 x increase, y goes up by 600-100 = 500

slope for C is

1/250

slope for D is

756/3

The greatest one out of these options is D, 756/3

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Ksivusya [100]
Are you asking for the whole sheet? But the first would have both P and Q I think would be in in quadrant three. If you want more, just remember that the top right corner is 1, the top left is 2, bottom left is 3, and bottom right is 4.
3 0
2 years ago
An object is launched directly upward with an initial velocity of 64 feet per second from a platform 80 feet high. What will be
LekaFEV [45]

Answer:

a) 63.6 ft

b) 1.99 seconds

c) 4.98 seconds

Step-by-step explanation:

a) The object will reach maximum height when its final velocity, v, is 0 m/s.

We apply one of Newton's equations of motion to solve this:

v^2 = u^2 - 2gh

where u = initial velocity = 64 ft/s

g = acceleration due to gravity = 32.2 ft/s

h = height reached by object.

Note: the equation has a negative sign because the object is going upwards, against gravity.

Hence:

0^2 = 64^2 - 2*32.2*h\\\\=> 64.4h = 4096\\\\h = 4096 / 64.4\\\\h = 63.6 ft

The object is now 63.6 ft above the platform (143.6 ft above the ground).

b) Time taken to get to that height can be gotten by using another one of Newton's equations:

v = u - gt

=> 0 = 64 - 32.2t

32.2t = 64\\\\=> t = 64 / 32.2 \\\\t = 1.99 secs

It took the object 1.99 secs to get to that height.

c) When the object begins falling to ground level, it is at a height, h =  143.6 ft and begins moving at initial velocity, u = 0 m/s.

Applying another of Newton's equations of motion, we have that:

h = ut + \frac{1}{2}gt^2

where t is the time taken to hit the floor after it begins its descent.

Therefore,

143.6 = 0*t + \frac{1}{2}*32.2t^2\\ \\143.6 = 16.1t^2\\\\t^2 = 143.6 / 16.1\\\\t^2 = 8.92\\\\t = \sqrt{8.92} \\\\t = 2.99 secs

This is the time it will take the object to hit the floor after it begins its descent.

Therefore, the total time it will take for the object to hit the ground after it is launched will be:

T = time taken to reach maximum height + time taken to hit the floor after it begins descending

T = 1.99 + 2.99

T = 4.98 seconds

6 0
3 years ago
A survey is being conducted in a city with 1 million residents. It would be far too
Irina18 [472]

Answer: Find answers in the attached documents

Step-by-step explanation:

7 0
3 years ago
Find the domain and range of the graph
asambeis [7]

Answer:

domain= -1, 3

range = -1, 1

Step-by-step explanation: ok

4 0
3 years ago
Can the polynomial below be factored into a perfect square? If not, select the answer that best describes why not.
pickupchik [31]

Answer:

C. It cannot be factored into a perfect square.

Step-by-step explanation:

Take the square roots of all the numbers present (64, 49, 8) and you will find that 8, the constant, is not a perfect square.

8 0
2 years ago
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