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klasskru [66]
3 years ago
13

What is the inverse of y=r? + 8?

Mathematics
1 answer:
Maru [420]3 years ago
6 0

Answer:

F-1(x)=x+8

Step-by-step explanation:

What is the inverse of y=r? + 8?

I hope this help.

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2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email&#160;protected]</a> - <a href
Phantasy [73]

Answer:

Step-by-step explanation:

2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3})  } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}

\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)

or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )

5 0
3 years ago
Use spherical coordinates. Evaluate e underroot x2 + y2 + z2 dV, where E is enclosed by the sphere x2 + y2 + z2 = 81 in the firs
aniked [119]

Answer:

The answer is below, see below:

Step-by-step explanation:

6 0
3 years ago
Please help. Explain using complete sentences
solniwko [45]
It would be an over-estimate if u rounded ur numbers up and an under-estimate if u rounded ur numbers down
7 0
3 years ago
Read 2 more answers
Give another name for AE
Gnoma [55]

Answer:  \text{Line AE}=\overleftrightarrow{EA},\quad  \overleftrightarrow{DA}, \quad \overleftrightarrow{AD},\quad \overleftrightarrow{ED},\quad \overleftrightarrow{DE},\quad \text{line r}

               \text{Segment AE}=\overline{EA}

<u>Step-by-step explanation:</u>

The line can be named using ANY two points on the line or using the lower case letter.

The segment can be named by placing the letters in any order.

\overline{AE}=\overline{EA}

4 0
4 years ago
What is the inverse of the function f(x) =1/9x + 2?
Fittoniya [83]

f(x) = 1/9x + 2

To find the inverse, we need to do this:

Replace f(x) with y

y = 1/9x + 2

Replace x with y

x = 1/9y + 2

Solve for y

Subtract 2

x - 2 = 1/9y

Multiply by 9

9x - 18 = y

Replace y with f^-1(x)

f^-1(x) = 9x - 18



5 0
3 years ago
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