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Sholpan [36]
2 years ago
11

A right cylinder is sliced perpendicular to it's base. What is the shape of the resulting two dimensional cross section?

Mathematics
1 answer:
Natalka [10]2 years ago
4 0
It would beA rectangle
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PLS HELP BRAINLIEST FOR CORRECT ANSWER+20 POINTS
svetoff [14.1K]

Answer:

120 blocks total

Step-by-step explanation:

All of the little cubes have side length 2"  Thus, the 11" height of the box cannot be used entirely:  we waste the top 1" because the five layers of little cubes reach only to 10" from the bottom.

Start at the bottom of the box.  The dimensions of the bottom are 12" by 8".  Along the longer side we can lay 6 blocks (which add up to 12" and are 2" wide.  We can add 3 more such rows to fill the available 8" width of the box bottom.  That's 6*4, or 24 blocks.

We can add 4 more 6 block by 4 block layers before we have the maximum 5 layers stacked in the box.

5 layers times 24 blocks per layer comes to 120 blocks total.

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B) 43 because they increase 3
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69 = 50 + s; 17, 18, 19
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I am not sure how to slove
notsponge [240]

First .... the limit of the given function is NOT EQUAL to 5 (it diverges so it has no limit).  There is a typo.  The 14 should be positive.

\lim_{x \to\ 7} \bigg(\dfrac{x^2-9x+14}{x-7}\bigg)=5

The precise definition of a limit is:

\text{If for every } \epsilon>0\text{ there exists a }\delta >0\text{ such that}\\|f(x)-L|

Given:

f(x) = \dfrac{x^2-9x+14}{x-7}\\\\L=5\\\\a=7\\\\\\|f(x)-L|

⇒ \epsilon = \delta

When ε = 0.1,     δ = 0.1

When ε = 0.01,   δ = 0.01

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2 years ago
Use the formula s - 25,000(1.032) to calculate your salary after 6 years. Round your answer to the nearest dollar
aleksandr82 [10.1K]

Answer:

A) $30201

Step-by-step explanation:

The formula S=25000(1.032)^t describes a 3.2% growth in salary for every year where the principal value is $25000 and the time "t" is the amount of years. This is known as exponential growth.

Since t=6:

S=25000(1.032)^6

S=30200.78

Rounded to the nearest dollar is $30201. So A is the correct choice.

3 0
3 years ago
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