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Sholpan [36]
2 years ago
11

A right cylinder is sliced perpendicular to it's base. What is the shape of the resulting two dimensional cross section?

Mathematics
1 answer:
Natalka [10]2 years ago
4 0
It would beA rectangle
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The area of a circle is 706.9 square inches. Find the radius
antoniya [11.8K]

Answer:

15 inches

Step-by-step explanation:

The area of a circle is pi r^2. We basically have to work backwards. I divided it fist by 3.14 which is the value of pi. I got 225.127, but I rounded it to 225. I found the square root of this which is 15. If we check the work. 15^2 is 225, and 225 times pi is 706.9.  

4 0
3 years ago
How do I construct a sample data set for which n=7, x=9(x bar), and s=0?
JulijaS [17]
When the standard deviation = 0, there is no deviation at all. So the numbers are all the same. And there are seven of them. And the average is nine. 
So the sample data set would just be seven 9s. 
4 0
3 years ago
I don’t know how you do 17.1 divided by 0.9.
andreyandreev [35.5K]
The answer is 19


work :

1-multiply the numbers by a submultiple of 10 to remove the decimal points.
17.1 \times 10 = 171 \\  \\ 0.9 \times 10 = 9

2-

now do the division :
171 \div 9 = 19

so the answer is 19



note: there is no need to get it back to decimal number unless you multiply just one of the numbers or multiply the numbers with different submultiples of 10



good luck
7 0
3 years ago
Read 2 more answers
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
Solving equations using Zero-Product property
FrozenT [24]

Answer:if y=0

Step-by-step explanation: view y as 0, so you have 2*0*(-8+0+7)=0

every number multiplied by 0 is 0 so 2*0 is 0 then in the brackets you will have -1. So the final line is 0*-1=0 like I said every number multiplied for 0 is 0 the equation is true for y=0

7 0
3 years ago
Read 2 more answers
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