Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
26.35 cc / 4 cm² =
<span>
<span>
<span>
6.5875
</span>
</span>
</span>
centimeters
Answer:
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Answer:
the second one is the answer
Answer:
942
Step-by-step explanation :
so your d is 300 so your r = 300/2= 150
a=3.14*r*r= 3.14*150*150= 70650
c= 3.14*d= 3.14*300= 942
_________________________________________________
OR
The curved surface area of solid cylinder is
As we are given that:
Diameter of solid cylinder = 8 cm
Length or Height o solid cylinder = 140 cm
Formula used to calculate the curved surface area of cylinder is:2n x h
Curved surface area of cylinder =2r x h
where,
r = radius of cylinder
h = height or length of cylinder
Radius of cylinder = daimeter
Now putting all the given values in above formula, we get:
Curved surface area of cylinder = 2x 22/7 x 140cm
Curved surface area of cylinder = 
Therefore, the curved surface area of solid cylinder is3520cm^{2}
