Answer:
the probability of no defects in 10 feet of steel = 0.1353
Step-by-step explanation:
GIven that:
A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.
Let consider β to be the average value for defecting
So;
β = 2
Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.
Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2
i.e

the probability mass function can be represented as follows:

where;
y = 0,1,2,3 ...
Hence, the probability of no defects in 10 feet of steel
y = 0


P(y =0) = 0.1353
(x + y = 29)
(y = 29 - x)
(5x + 2(29 - x) = 100)
(5x + 58 - 2x = 100)
(3x = 42)
(x = 14)
(y = 15)
(14 5-point questions and 15 2-point questions)
Answer:
24
Step-by-step explanation:
Answer:
the answer is x=2 and y=2
Step-by-step explanation:
-3y=16+5x
-y=(16+5x)3
Common factors of 60 and 126 are:
1, 2, 3, 6
Hope this helps