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3 years ago

6

Please help I will give out brainliest

2 answers:

kogti [31]3 years ago

7 0

Answer:

upper bound = 112.5

lower bound = 111.5

Step-by-step explanation:

x = 360 - 59 - 108 - 81

x = 112°

upper bound = 112.5 < 113

lower bound = 111.5 < 112

so

L.B. U.B.

111.5 < 112 < 112.5

velikii [3]3 years ago

4 0

Answer:

upper bound = 112.5

lower bound = 111.5

Step-by-step explanation:

x = 360 - 59 - 108 - 81

x = 112°

upper bound = 112.5 < 113

lower bound = 111.5 < 112

so

L.B. U.B.

111.5 < 112 < 112.5

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The temperature, T, of a given mass of gas varies inversely with its Volume,V. The temperature of 98 cm ³ of a certain gas is 28

Naily [24]

Answer:

T₂ = 421.4 K

Step-by-step explanation:

The temperature, T, of a given mass of gas varies inversely with its Volume,V.

$T\propto \dfrac{1}{V}\\\\V_1T_1=V_2T_2$

We have,

V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K

V₂ = 70 cm₃

We need to find the new temperature of the gas. Using the above relation to find T₂.

$T_2=\dfrac{V_1T_1}{V_2}\\\\T_2=\dfrac{98\times 301}{70}\\\\T_2=421.4\ K$

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3 years ago

75 people to 25 people what is the percentage of the change?

garri49 [273]

75-25=50
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4 years ago

Read 2 more answers

Answer this please thanks

taurus [48]

Answer:

No

Step-by-step explanation:

The first 3 boxes are proportional since they have a ratio of 1:3, but 6:21 is not proportional to the others.

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3 years ago

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H(x)=-x^2+6x. So what is the value of h(2)

crimeas [40]

✩ Answer:

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*

$\bold{Hello!}\\\bold{Your~answer~is~below!}$

✩ Step-by-step explanation:

✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*✧･ﾟ: *✧･ﾟ:*

✺ Quadratic polynomials can be factored using the transformation $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ , where $x_{1}$ and $x_{2}$ are the solutions of the quadratic equation $ax^2+bx+c=0$ :

$-x^2+6x=0$

✺ All equations of the form $ax^2+bx+c=0$ can be solved using the quadratic formula:

$-b=\frac{+}\\\sqrt{b^2-4ac}\\~~~~~~~~~~~~~2a$

✺ The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction:

$x=\frac{\sqrt{-6\frac{+}\\\sqrt{6^2}}}{2(-1)}$

✺ Take the square root of $6^2$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{2(-1)}$

✺ Multiply $2$ times $-1$ :

$x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is plus. Add $-6$ to $6$ :

$x=\frac{0}{-2}$

✺ Divide $0$ by $-2$ :

$x=0$

-OR-

✺ Now solve the equation $x=\frac{\sqrt{-6\frac{+}\\{6}}}{-2}$ when ± is minus. Subtract $6$ from $-6$ :

$x=\frac{-12}{-2}$

✺ Divide $-12$ by $-2$ :

$x=6$

✺ Optional : Factor the original expression using $ax^2+bx+c=a(x-x_{1})(x-x_{2} )$ . Substitute $0$ for $x_{1}$ and $6$ for $x_{2}$ :

$-x^2+6x=-x(x-6)$

✩ Answer:

✺ <u>Factored Form</u>: $x(x-6)$

✺ <u>Exact Form</u>: $x=6$

✺ <u>Graph Point Form</u>: $x=(6,0)$

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4 years ago

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Step-by-step explanation:

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2 years ago