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2 years ago

What’s the domain and range of this graph?

Mathematics

1 answer:

avanturin [10]2 years ago

3 0

Given:

The graph of a downward parabola.

To find:

The domain and range of the graph.

Solution:

Domain is the set of x-values or input values and range is the set of y-values or output values.

The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.

Domain = R

Domain = (-∞,∞)

The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.

From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.

Range = All real numbers less than or equal to -4.

Range = (-∞,-4]

Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].

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A scalene triangle is an isosceles triangle. true false

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3 years ago

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Alla [95]

Answer:

2.3%

Step-by-step explanation:

The formula to convert x into z distribution is

$z=\frac{x-\mu}{\sigma}$

Where z is the test statistic

x is what we are looking for (in this case 37)

$\mu$ is the mean (in this case, it is 25)

$\sigma$ is the standard deviation (we have 6)

<em>Plugging these into the formula, we get:</em>

$z=\frac{x-\mu}{\sigma}\\z=\frac{37-25}{6}\\z=2$

Thus we can say we want $P(z\geq 2)$

<u>Note: </u> $P(z\geq a)=1-P(z\leq a)$

The table given is for any z where $P(z\leq a)$

Thus, now we have:

$P(z\geq 2)\\=1-P(z\leq 2)\\=1-0.9772\\=0.0228\\$

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Rounded, we get 2.3%

Third answer choice is right.

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3 years ago

PLS HELP WILL MARK BRAINLIEST

gavmur [86]

Answer:

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2. Rolling a 2

Again, it is more likely that the result will be one of the other 5 numbers. But obviously a 2 is still an option, so it's not impossible.

3. Rolling a number less than 10

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3 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
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\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

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3 years ago

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katovenus [111]

Answer:

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Step-by-step explanation:

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