Hey there! I'm happy to help!
Let's represent our number of quarters with q and our dimes with d. We know that each q has a value of 0.25, and each d has a value of 0.1. This means that 0.25q+0.1d=1.85. We also know that q+d=11 as there are 11 total coins.
Here is our system of equations.
0.25q+0.1d=1.85
q+d=11
We are asked to solve with elimination. To do this, we need combine the equations to cancel out a variable to solve for the other. We have 1d on the bottom. Let's multiply the entire top equation by -10 to get a -1d on the top so we can do this.
-2.5q-d=-18.5
q+d=11
We combine the equations.
-1.5q=-7.5
We divide both sides by -1.5
q=5
Since there are 11 coins in total, this means that there are 5 quarters and 6 dimes.
Have a wonderful day!
The answer is c
(0,8) is the y intercept so the +.. is +8
then pug in 4 to x and find which one equal 0
There is no solution.
If you divide both sides by -3 to get the variable isolated, it is
|s| = -6
Absolute value equations cannot equal negative numbers, so there is no solution.
Answer:
A=1981.34
Step-by-step explanation:
A=pi*r square
631*3.14=1981.34