Question 7:
Diameter = 6.2 cm so Radius = 3.1 cm
A=πr² = 3.14 × 3.1² = 30.1754 cm² = 30.18 cm²
Question 8:
Circumference = 2πr
16π = 2πr
therefore 16 = 2r so r = 8cm
2 × c ÷ 7 ÷ 2. This better?
Answer:
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.
Step-by-step explanation:
Given that,
For the first 9 holes X:
E(X) = 80
SD(X)=13
For the second 9 holes Y:
E(Y) = 80
SD(Y)=13
For the sum W=X+Y, the following properties holds for means , variance and standard deviation :
E(W)=E(X)+E(Y)
and
V(W)=V(X)+V(Y)
⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

∴E(W)=E(X)+E(Y) = 80 +80=160
and
∴



Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.
Answer:
The answer is c.) 5(2)+2(6-3)
Step-by-step explanation:
This is an addition problem, because you are solving for the multiplied numbers added together.
5(2)+ 2(6-3)
10+(12-6)
10+6
= 16 I hope this help :)