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s344n2d4d5 [400]
2 years ago
14

Is 3x+2x=3 a function

Mathematics
1 answer:
trasher [3.6K]2 years ago
8 0
Yes this is a function
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I need help please! i dont know!
Kaylis [27]

Answer:

there is a 12.5% increase

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2 years ago
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Convert the percent to a decimal, and then divide. 7% ÷ 4
Inessa05 [86]
7% = 0.07
0.07/4 = 0.0175

The answer is 0.0175
3 0
3 years ago
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The perimeter of a rectangular field is 380 yd. the length is 70 yd longer than the width. find the dimensions.
GaryK [48]
P=2L+2W
380=2*70+2W
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The dimensions are 70 yd and 120 yd

Hope this helps!
3 0
2 years ago
Kelsey graphed the equation y = 3x + 1 as shown below.
USPshnik [31]

Answer:

D. Kelsey graphed the slope as the y-intercept and the y-intercept as the slope.

Step-by-step explanation:

The equation to graph was : y= 3x + 1 where the slope is 3 and the y-intercept is 1

However, Kelsey graph line passes through points (-3, 0)and (0, 3).From these points the equation of the line is;

m=Δy/Δx  where

m=the slope of the graph

Δy= 3-0 =3

Δx= 0--3 =3

m=3/3 = 1

The equation of the line should be;

m=Δy/Δx

1=y-3/x-0

1x= y-3

3+1x= y

y= 1x + 3 ----------where the slope is 1 and y-intercept is 3

So you can see here that in the original equation,<em> the slope m is 3 and y-intercept is 1 as shown in the first attached graph.</em>

While in the Kelsey's graph, <em>the slope is 1 and the y-intercept is 3 as in the second attached graph. </em>

<em>Thus, the correct answer is D : Kelsey graphed </em><u><em>the slope,3</em></u><em> as the </em><em>y-intercept </em><em>and the</em><u><em> y-intercept,1,</em></u><em> as the slope. </em>

Answer choice A is incorrect because Kelsey didnot graph the y-intercept, 1 on the x-axis but graphed point (-3,0) on the x-axis.

Answer choice B is incorrect because on Kelsey's equation the y-intercept is 3 and not -3. i.e. y=1x + 3

Answer choice C is incorrect because Kelsey graphed the slope as up 1 right 1 which is okay per the equation , y=1x+3.However, this incorrect because the correct graph has a slope of 3.

4 0
3 years ago
Read 2 more answers
Consider the set T = {1, 2, 3, 4, 5, 6}. Let R = {(a, b) | a divides b} be a relation on the set T. Identify the missing ordered
serg [7]

Answer:  The missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

Step-by-step explanation:  We are given the following set :

T = {1, 2, 3, 4, 5, 6}.

And, R = {(a, b) | a divides b} be a relation on the set T.

We are to identify the missing pairs from the following list of all ordered pairs in the given relation R on the set T :

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), _____, (4, 4), (5, 5), and (6, 6).}.

Since R contains the ordered pairs (a, b) such that a divides b, so all the ordered pairs in R are

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 2), (2, 4), (2, 6), (3, 3), (3, 6), (4, 4), (5, 5), and (6, 6).

Thus, the missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

4 0
3 years ago
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