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CaHeK987 [17]
3 years ago
6

James has 5 friends who are available to go to a baseball game with him, but he only has 2 extra tickets how many different choi

ces
does james have for which 2 friends to invite
Mathematics
2 answers:
bearhunter [10]3 years ago
7 0
4 different choices
Sliva [168]3 years ago
4 0

It is given that James has 5 friends who are available to go to a baseball game with him, but James has only has 2 extra tickets. This is a perfect example of a combinations question and we have been asked to choose 2 from a given 5. This can be spoken of as: Given 5 choose 2 and can be represented mathematically as a Combination:

^5C_2=\frac{5!}{2!(5-2)!}=\frac{5!}{2!3!} =\frac{5\times 4\times 3!}{2\times 3!}=10

Thus, James has 10 different choices to invite 2 friends.

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An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24
melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}

z = -0.68

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

7 0
2 years ago
The sets A,B and C in a universal set consisting of the first 10 lower case letters of the alphabet are: A={a,b,c}, B={b,c,a,e},
Papessa [141]

Answer:

Which item fits in the left side of the table?Criminal versus Civil Cases Criminal cases Civil cases ? . • Accuser is called the plaintiff • Lower burden of proof Defendant may be found liable • Usually heard by a judge only • Accused not guaranteed an attorney

A. No burden of proof

B. Accuser is called the defendant

C. Defendant may be found guilty

D. Usually heard by a jury only

8 0
3 years ago
Researchers fed mice a specific amount of Toxaphene, a poisonous pesticide, and studied their nervous systems to find out why To
Mkey [24]

Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b.  90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

c. Yes, the data give good evidence to support this theory

Step-by-step explanation:

a.  The table below shows the calculations:

                 X                (X-mean)^2

                1.7             0.0225

                1.8                 0.0025

                1.9                 0.0025

                2.0                 0.0225

Total        7.4                  0.05

Sample size: n=4

The mean is:  \bar{x} = \frac{7.4}{4} = 1.85

The sample standard deviation, s = \sqrt{\frac{\sum \left ( x-\bar{x} \right )^{2}}{n-1}}=0.1291

The standard error, se= \frac{s}{\sqrt{n}}=\frac{0.1291}{2} = 0.06455

b. Degree of freedom: df = n-1 = 3

Critical value of t for 90% confidence interval is: 2.3534

The confidence interval is  \bar{x}\pm t_{c}se = 1.85\pm 2.3534\cdot 0.06455=1.85\pm 0.1519 = (1.6981, 2.0019)

c. The Hypotheses are:

H_{0}:\mu=1.3,H_{1}:\mu>1.3

So the test statistics will be

t=\frac{\bar{x}-\mu}{s/\sqrt{n}}=8.52

The p-value is: 0.0017

We reject the null hypothesis because p-value is less than 0.05 . This indicates that the data gave good evidence to support this theory.

4 0
3 years ago
Please, provide an explanation and answer
Helen [10]

Answer:

whats the question

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The population of Mexico has been increasing at an annual rate of 1.7%. If the population was 100,350,000 in the year 2000, pred
Svetllana [295]

We can withdraw a equation to give mexico population

P = M.(1 + i)^t

So,

First of all, how many years passed? 2015 - 2000 = 15. Our time is 15, our annual rate is 1,7%, time to calc.

P = 100350000.(1 + 1,7%)^15

1,7% = 0,017

P = 100350000.(1 + 0,017)^15

P = 100350000.(1,017)^15

P = 100350000.1,2876988084901218382866596204289

P = 129220575,43198372647206629291004

Rounding

P = 129,220,575

8 0
3 years ago
Read 2 more answers
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