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3 years ago

PLEASE HELP ASAP!!!!!!

Mathematics

1 answer:

Andru [333]3 years ago

7 0

Answer:

it's C ;)) maybe i guess-

Step-by-step explanation:

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If someone could explain what I am supposed to do and how to do it, I would greatly appreciate that! I will give thanks and mark

Andreas93 [3]

By comparing equation
a=2,
x-h=x+1, -h=1, h=-1
k=-3
h=-1 move graph to the left (because h=-1 is negative) by 1 unit, h is moving to the left or to the right(horizontal shift)
a=2 vertical streaching
k=-3, k shows vertical shift , k=-3 moving 3 units down because it is negative

4 0

3 years ago

The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k

HACTEHA [7]

Answer:

The given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is $f(x)=\frac{2x}{3}-4\hfill (1)$

and when x=x+k then $f(x+k)=\frac{2x}{3}-6\hfill (2)$

Now to find the value of k:

Put x=x+k in the function f(x)

$f(x)=\frac{2x}{3}-4$

$f(x+k)=\frac{2(x+k)}{3}-4$

$f(x+k)=\frac{2x+2k}{3}-4\hfill (3)$

Now comparing equations (2) and (3) we get

$f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2k}{3}+2=0$

$\frac{2k}{3}=-2$

$k=\frac{-2\times 3}{2}$

$k=-3$

Therefore k=-3

Therefore the given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

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3 years ago

Please help asap math problem I don't understand

Karolina [17]

The first table is a function. The second table is not because the x value 3 has two y values of 3 and 5. Change one of the x values of 3 to 2 and it would be a function. (Change (3,3) to (2,3) or (3,5) to (2,5), or any number that isn't already listed as an x value)

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3 years ago

9. Which of the following is the interquartile range of the data set shown below?

Semmy [17]

Answer:

Step-by-step explanation:

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3 years ago

Find The missing length

Reil [10]

C is the hypotenuse of a right triangle whose leg lengths are 7 and 9. Thus,

c^2 = 7^2 + 9^2 = 49 + 81 = 130.

Then c = sqrt(130) (answer)

7 0

3 years ago