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3 years ago

I need help on my math homework

Mathematics

1 answer:

wolverine [178]3 years ago

7 0

Write down equations what you know.

NML is 28x-1, this is the total angle.
NME is 5x-1, this is the small part of the angle
EML is 115, this is the large part of the angle

So,
NME + EML should equal NML
5x-1 + 115 = 28x-1
Solve for x
Add 1 both sides
5x+115 = 28x
Subtract 5x both sides
115 = 23x
Divide 23 both sides
X=5

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The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?

Kamila [148]

<h2><u>Diagram</u><u>:</u><u>-</u></h2>

$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}$

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

${\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}$

Substitute the values

${:}\longmapsto$ $\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }$

${:}\longmapsto$ $\sf a=\sqrt {(3)^2+(4)^2}$

${:}\longmapsto$ $\sf a=\sqrt {9+16}$

${:}\longmapsto$ $\sf a=\sqrt{25}$

${:}\longmapsto$ $\sf a=5cm$

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

$\boxed{\sf Perimeter=4a}$

Substitute the values

${:}\longmapsto$ $\sf Perimeter=4×5$

${:}\longmapsto$ $\sf Perimeter=20cm$

$\therefore$ Perimeter of the rectangle is 20cm.

5 0

3 years ago

Look at the following graph of the given equation. Determine whether the equation is a function. Explain why or why not.

Vadim26 [7]

The equation $y=2x+2$ is a function

Explanation:

Given that the graph contains the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$

We need to determine whether the equation $y=2x+2$ is a function.

To determine the equation is a function, let us substitute the coordinates in the equation and check whether it satisfies the equation.

Let us substitute the coordinate $(-1,0)$ in the equation $y=2x+2$

Thus, we have,

$0=2(-1)+2$

$0=-2+2$

$0=0$

Thus, the coordinate $(-1,0)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(0,2)$ in the equation, we have,

$2=2(0)+2$

$2=2$

Thus, the coordinate $(0,2)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(1,4)$ in the equation $y=2x+2$

$4=2(1)+2$

$4=4$

Thus, the coordinate $(1,4)$ satisfies the equation $y=2x+2$

Substituting the coordinate $(2,6)$ in the equation, we get,

$6=2(2)+2$

$6=6$

Thus, the coordinate $(2,6)$ satisfies the equation $y=2x+2$

Hence, the coordinates $(-1,0)$ , $(0,2)$ , $(1,4)$ and $(2,6)$ satisfies the equation $y=2x+2$

Thus, the equation $y=2x+2$ is a function.

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4 years ago

Find the area of the circle.<br> Use 3.14 for π.<br> d = 10 cm<br> A = [?] cm²<br> A=TCr2

Stells [14]

Answer:

78.5

Step-by-step explanation:

The diameter (d) is equal to the radius x 2, so take half of d to get r. Use r (5) in the equation to get your answer.

A= 3.12 x 5^2

A= 78.5

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3 years ago

I need help on my math homework ​

I need help on my math homework