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3 years ago

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I need help with inequalities

1 answer:

Hatshy [7]3 years ago

8 0

Answer: I can help

Step-by-step explanation:

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One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table.

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3 years ago

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What is the simplified form of this expression? (0.2)^5

Sidana [21]

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3 years ago

Calculate the variance for the data set. Round your answer to the nearest hundredth. Show all of your steps. { 10 , 19 , 21 , 28

GrogVix [38]

Answer:

Variance of the given data = 31.143

Explanation:

Variance, $\sigma^2=\frac{1}{n} \sum_{i=1}^{n}(x_i-\mu)^2$ , where n is the number of observations, μ is the mean and $x_i$ is the observations made.

Number of observations, n = 7

Mean, μ = $\frac{10+19+21+28+12+20+16}{7} = 18$

$\sum_{i=1}^{n}(x_i-\mu)^2=(10-18)^2+(19-18)^2+(21-18)^2+(28-18)^2+(12-18)^2+(20-18)^2+(16-18)^2\\ \\ \sum_{i=1}^{n}(x_i-\mu)^2=64+1+9+100+36+4+4=218$

$\sigma^2=\frac{1}{n} \sum_{i=1}^{n}(x_i-\mu)^2=\frac{218}{7} =31.143$

So variance of the given data = 31.143

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3 years ago

a student has reflected the patterns as given below are the reflections correct and what advice would yiu give them

siniylev [52]

Answer:

Step-by-step explanation:

We need the rest of the question please.

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3 years ago

Find the quadratic function y=ax^2 + bx + c whose graph passes through the given points. (-3,37), (2,-8), (-1,13)

melamori03 [73]

The quadratic function is $y=1x^{2} + (-8)x + 4$

Step-by-step explanation:

The quadratic function given is $ax^{2} + bx + c=y$

and same quadratic function is passes through (-3,37), (2,-8), (-1,13)

Replacing points one by one

we get,

For (-3,37) :

$a(-3)^{2} + b(-3) + c=37$

$9a + -3b + c=37$ =<em> equation 1 </em>

For (2,-8) :

$a(2)^{2} + b(2) + c=(-8)$

$4a + 2b + c=(-8)$ = <em>equation 2</em>

For (-1,13)

$a(-1)^{2} + b(-1) + c=(13)$

$a + -1b + c=13$ = <em>equation 3</em>

Solving the linear equation to get values of a,b,c

Subtract equation 2 with equation 3

we get, $(4a + 2b + c)-(a + -1b + c)=(-8)-13$

$(3a + 3b )=(-21)$

$(a + b )=(-7)$ = <em>equation 4</em>

Now, Subtract equation 1 with equation 2

we get, $(9a + -3b + c)-(4a + 2b + c)=(37)-(-8)$

$(5a - 5b )=(45)$

$(a - b )=(9)$ = <em>equation 5</em>

Now, Add equation 4 with equation 5

we get, $(a + b)+(a - b)=(-7)+(9)$

$(2a - 0b )=(2)$

$(a)=1$

Replacing value of a in <em>equation 5</em>

$(a - b )=(9)$

$(1 - b )=(9)$

$(b)=(-8)$

Replacing value of a and b in <em>equation 1</em>

$9a + -3b + c=37$

$9(1) + -3(-8) + c=37$

$9 + 24 + c=37$

$c=4$

Thus,

The quadratic function $y=1x^{2} + (-8)x + 4$

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4 years ago