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Alchen [17]
4 years ago
12

During the processing stage what does the computer do

Computers and Technology
1 answer:
Ann [662]4 years ago
5 0
<span>The finished product is "output." In the electronic computer, data are the raw material or input to the computer.</span>
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Give a recursive algorithm to compute the sum of the cubes of the first n positive integers. The input to the algorithm is a pos
DaniilM [7]

Answer:

def sum_cubes(n):

   if n == 1:

       return 1

   else:

       return n * n * n + sum_cubes(n-1)

print(sum_cubes(3))

Explanation:

Create a function called sum_cubes that takes one parameter, n

If n is equal to 1, return 1. Otherwise, calculate the cube of n, and add it to the sum_cubes function with parameter n-1

If we want to calculate the cubes of the first 3 numbers:

sum_cubes(3) = 3*3*3 + sum_cubes(2)

sum_cubes(2) = 2*2*2 + sum_cubes(1)

sum_cubes(1) = 1

If you substitute the values from the bottom, you get 27+8+1 = 36

7 0
3 years ago
Which view shows how the document will look when printed?
DIA [1.3K]
Please provide photos for your question.
7 0
4 years ago
The term “computer literacy” dates back to what decade? <br> 1960s<br> 1970s<br> 1980s<br> 1990s
NNADVOKAT [17]
1970-80s which is when some of the first computers were created like apple computers which looked like a giant cube and a rectangle on the side which is very different than what we have today.

Hope this helps!
3 0
4 years ago
Write a program which promptsuser to enter an integer value. Using while loop print the valuesfrom
tino4ka555 [31]

Answer:Following is the c++ code for the problem:

#include <iostream>

using namespace std;

int main() {

   int number;

   cout<<"Enter the number"<<endl;

   cin>>number;

   int i=0,c=0,odd[500];

   while(i<=number)//loop for printing the numbers form 0 to number.

   {

       cout<<i<<" ";

       if(i%2!=0)// storing in the odd array if the number is odd.

       {

           odd[c++]=i;//storing odd numbers..

       }

       i++;

   }

   cout<<endl;

   i=0;

   cout<<"The odd numbers are "<<endl;

   while(i<c)//loop to print the odd numbers.

   {

       cout<<odd[i]<<" ";

       i++;

   }

   cout<<endl<<"The prime numbers are "<<endl;

   i=0;

   int sum=0;

   

   while(i<c)//loop to print the prime numbers..

   {

       int div=2;

       while(div<odd[i])

       {

           if(odd[i]%div==0)

           break;

           div++;

       }

       if(div==odd[i])

      {

           cout<<odd[i]<<" ";

           sum+=odd[i];//updating the sum..

      }

       i++;

   }

   cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..

return 0;

}

Output :

Enter the number

49

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49  

The odd numbers are  

1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49  

The prime numbers are  

3 5 7 11 13 17 19 23 29 31 37 41 43 47  

The sum of odd prime numbers is 326 .

Explanation:

First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.

6 0
3 years ago
Why is Thomas Jefferson considered an accomplished man , or a Renaissance man?​
lesantik [10]
The term “Renaissance man” means for a very clever person to be good at many different things.
4 0
3 years ago
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