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2 years ago

Y (y + 2) = y2 - 6 also 2 [x - (1-3x)] = 3 (x + 1)

Mathematics

1 answer:

vladimir1956 [14]2 years ago

7 0

Answer:

Step-by-step explanation:

y(y+2)=y²-6

y²+2y=y²-6

2y=-6

y=-3

2[x-(1-3x)]=3(x+1)

2[x-1+3x]=3x+3

2(4x-1)=3x+3

8x-2=3x+3

8x-3x=3+2

5x=5

x=1

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What is 2 2/3 x 3 1/3 x 2 1/3

madreJ [45]

Answer:

20 20/27

Step-by-step explanation:

(2 2/3)(3 1/3)(2 1/3) = (8/3)(10/3)(7/3) = 560/27 = 20 20/27

_____

<em>Additional comment</em>

The first two numbers can be written as a difference and a sum:

= (3 -1/3)(3 +1/3)(2 1/3)

= (3·3 -1/3·3 +3·1/3 -1/3·1/3)(2 1/3)

= (9 -1/9)(2 +1/3) = 9·2 +9·1/3 -1/9·2 -1/9·1/3 = 18 +3 -6/27 -1/27

= 20 20/27

7 0

2 years ago

Select all that apply.

Kryger [21]

Answer:

Your answer would be

$1 \times 3 = 3$

And

$3 \times 5 = 15$

Step-by-step explanation:

Hope this helps. If I am wrong, REPORT ME PLEASE.

6 0

2 years ago

What is 126 billion divied by 108.2 billion

LUCKY_DIMON [66]

the answer is 0.00116451016

hope it helped :)

4 0

3 years ago

Read 2 more answers

A card is drawn at random from a deck of 52 playing cards. Find the probability that the card drawn is:

melomori [17]

probability that the card drawn is:

an ace or a king = 0.1538
a king or a diamond = 0.3269

<u>Step-by-step explanation:</u>

Here we have , A card is drawn at random from a deck of 52 playing cards. We need to find that Find the probability that the card drawn is:

an ace or a king

A deck of standard 52 cards contain four aces. There are four kings in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{8}{52}$

⇒ $probability = 0.1538$

a king or a diamond

A deck of standard 52 cards contain four kings. There are 13 Diamonds in a standard deck of playing cards. So ,we need to find probability that card drawn is either a ace or king i.e.

$probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{Number-of-(ace+king)-cards}{total-number-of-cards}$

⇒ $probability = \frac{(13+4=17)}{52}$